Central Tendency & DispersionPYQ Dec 21Question 3033 of 473
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Given that mean = 70.20 and mode = 70.50, the Median is expected to be.

Options

A70.15
B70.20
C70.30
D70.35
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Correct Answer

✅ Option c — 70.30

All Options:

  • A70.15
  • B70.20
  • C70.30
  • D70.35

Detailed Solution & Explanation

**Step 1: Apply the empirical formula.** Mode=3×Median−2×Mean\text{Mode} = 3 \times \text{Median} - 2 \times \text{Mean} **Step 2: Substitute values.** - Mode = 70.50, Mean = 70.20 70.50=3×Median−2×70.2070.50 = 3 \times \text{Median} - 2 \times 70.20 70.50=3×Median−140.4070.50 = 3 \times \text{Median} - 140.40 3×Median=70.50+140.40=210.903 \times \text{Median} = 70.50 + 140.40 = 210.90 Median=210.903=70.30\text{Median} = \frac{210.90}{3} = 70.30 Hence, **Option C** is the correct answer.

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