Central Tendency & DispersionPYQ Jun 23Question 3037 of 473
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For a moderately skewed distribution of marks in statistics for a group of 200 students, the mean marks and median marks are 55.60 and 52.40, respectively. What are the modal marks?

Options

A54.43
B58
C53.56
D46
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Correct Answer

✅ Option d — 46

All Options:

  • A54.43
  • B58
  • C53.56
  • D46

Detailed Solution & Explanation

**Step 1: Apply the empirical formula.** Mode=3×Median−2×Mean\text{Mode} = 3 \times \text{Median} - 2 \times \text{Mean} **Step 2: Substitute values.** - Mean = 55.60, Median = 52.40 Mode=3×52.40−2×55.60\text{Mode} = 3 \times 52.40 - 2 \times 55.60 =157.20−111.20=46.00= 157.20 - 111.20 = 46.00 Hence, **Option D** is the correct answer.

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