Central Tendency & DispersionPYQ Sep 24Question 3045 of 473

If the mean and median of a moderately asymmetrical series are 70.8 and 68.6 respectively, then the most probable mode is:

Options

A75.2

B64.2

C63.4

D72.5

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Correct Answer

✅ Option b — 64.2

All Options:

A75.2
B64.2
C63.4
D72.5

Detailed Solution & Explanation

**Step 1: Apply the empirical formula.**

\text{Mode} = 3 \times \text{Median} - 2 \times \text{Mean}

**Step 2: Substitute values.** - Mean = 70.8, Median = 68.6

\text{Mode} = 3 \times 68.6 - 2 \times 70.8

= 205.8 - 141.6 = 64.2

Hence, **Option B** is the correct answer.

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