Central Tendency & DispersionMTP June 24 Series IIIQuestion 3071 of 473
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If the arithmetic mean between two numbers is 64\displaystyle 64 and the Geometric Mean between them is 16\displaystyle 16. The Harmonic mean between them is

Options

A64\displaystyle 64
B4\displaystyle 4
C16\displaystyle 16
D40\displaystyle 40
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Correct Answer

✅ Option b — 4\displaystyle 4

All Options:

  • A64\displaystyle 64
  • B4\displaystyle 4
  • C16\displaystyle 16
  • D40\displaystyle 40

Detailed Solution & Explanation

**Step 1: Apply the formula GM² = AM × HM.** HM=GM2AM=16264=25664=4\text{HM} = \frac{\text{GM}^2}{\text{AM}} = \frac{16^2}{64} = \frac{256}{64} = 4 The Harmonic Mean = 4\displaystyle 4 = **Option B**. Note: The exam key says A (64\displaystyle 64), but mathematically HM = GM²/AM = 256/64 = 4 (Option B). Hence, **Option B** is the correct answer.

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