Central Tendency & DispersionPYQ July 21Question 3077 of 473
All Questions

If the relationship between x\displaystyle x and y\displaystyle y is given by 2x+3y=10\displaystyle 2x + 3y = 10 and the range of y\displaystyle y is 10\displaystyle 10, then what is the range of x\displaystyle x?

Options

A10
B18
C8
D15
For any discrepancies in this question, email contact@cadada.in

Correct Answer

✅ Option d — 15

All Options:

  • A10
  • B18
  • C8
  • D15

Detailed Solution & Explanation

**Step 1: Express x\displaystyle x in terms of y\displaystyle y.** From 2x+3y=10\displaystyle 2x + 3y = 10: x=10−3y2=5−32yx = \frac{10 - 3y}{2} = 5 - \frac{3}{2}y **Step 2: Apply the range transformation rule.** If x=a+by\displaystyle x = a + by, then Range(x)=∣b∣×\displaystyle (x) = |b| \times Range(y)\displaystyle (y). Here b=−32\displaystyle b = -\frac{3}{2}. **Step 3: Calculate Range of x\displaystyle x.** Range(x)=∣−32∣×10=32×10=15\text{Range}(x) = \left|-\frac{3}{2}\right| \times 10 = \frac{3}{2} \times 10 = 15 Hence, **Option D** is the correct answer.

More Questions from Central Tendency & Dispersion

Ready to Master Central Tendency & Dispersion?

Practice all 473 questions with instant feedback, earn XP, track your streaks, and ace your CA Foundation exam.

Start Practicing — It's Free