Measures of Central Tendency and DispersionMCQPYQ July 21Question 3094 of 473
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The probable value of mean deviation when Q3=40\displaystyle Q_3 = 40 and Q1=15\displaystyle Q_1 = 15 is:

Options

A15
B18.75
C17.50
D0
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Correct Answer

Option a15

All Options:

  • A15
  • B18.75
  • C17.50
  • D0

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Detailed Solution & Explanation

We are given: - Third quartile: Q3=40\displaystyle Q_3 = 40 - First quartile: Q1=15\displaystyle Q_1 = 15 1. Calculate Quartile Deviation (Q.D.): Q.D.=Q3Q12=40152=12.5\text{Q.D.} = \frac{Q_3 - Q_1}{2} = \frac{40 - 15}{2} = 12.5 2. For a normal distribution, the relationship between Quartile Deviation (Q.D.) and Mean Deviation (M.D.) is: Q.D.56 M.D.    M.D.65 Q.D.\text{Q.D.} \approx \frac{5}{6} \text{ M.D.} \implies \text{M.D.} \approx \frac{6}{5} \text{ Q.D.} 3. Calculate Mean Deviation: M.D.1.2×12.5=15\text{M.D.} \approx 1.2 \times 12.5 = 15 Hence, **Option A** is the correct answer.

About This Chapter: Measures of Central Tendency and Dispersion

Paper

Paper 3: Quantitative Aptitude

Weightage

12-15 Marks

Key Topics

Mean, Median, Mode, Range, Mean Deviation, Standard Deviation

The core foundation of Statistics. This chapter covers Mean (Arithmetic, Geometric, Harmonic), Median, Mode, and their properties. It also explores measures of spread like Range, Mean Deviation, Standard Deviation, and Quartile Deviation.

View Official ICAI Syllabus

Exam Strategy Tip

Do not just memorize formulas; ICAI loves asking about the mathematical properties (e.g., 'sum of deviations from the AM is always zero'). You can usually eliminate 2 options just by knowing the properties.

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