Central Tendency & DispersionMTP Nov 18Question 3102 of 473
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The MD about the Mean for the data 6,9,11,10,12\displaystyle 6,9,11,10,12 is

Options

A1.47\displaystyle 1.47
B1.57\displaystyle 1.57
C1.67\displaystyle 1.67
D1.87\displaystyle 1.87
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Correct Answer

✅ Option c — 1.67\displaystyle 1.67

All Options:

  • A1.47\displaystyle 1.47
  • B1.57\displaystyle 1.57
  • C1.67\displaystyle 1.67
  • D1.87\displaystyle 1.87

Detailed Solution & Explanation

We are given the observations: 6,9,11,10,12\displaystyle 6, 9, 11, 10, 12. The number of observations is n=5\displaystyle n = 5. 1. Calculate the arithmetic mean (xˉ\displaystyle \bar{x}): xˉ=6+9+11+10+125=485=9.6\bar{x} = \frac{6 + 9 + 11 + 10 + 12}{5} = \frac{48}{5} = 9.6 2. Calculate absolute deviations from the mean ∣xi−xˉ∣\displaystyle |x_i - \bar{x}|: - ∣6−9.6∣=3.6\displaystyle |6 - 9.6| = 3.6 - ∣9−9.6∣=0.6\displaystyle |9 - 9.6| = 0.6 - ∣11−9.6∣=1.4\displaystyle |11 - 9.6| = 1.4 - ∣10−9.6∣=0.4\displaystyle |10 - 9.6| = 0.4 - ∣12−9.6∣=2.4\displaystyle |12 - 9.6| = 2.4 3. Calculate sum of absolute deviations: ∑∣xi−xˉ∣=3.6+0.6+1.4+0.4+2.4=8.4\sum |x_i - \bar{x}| = 3.6 + 0.6 + 1.4 + 0.4 + 2.4 = 8.4 4. Calculate Mean Deviation: M.D.=8.45=1.68\text{M.D.} = \frac{8.4}{5} = 1.68 Since 1.68\displaystyle 1.68 is the mathematically correct value, which is closest to 1.67\displaystyle 1.67, we select Option C. Hence, **Option C** is the correct answer.

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