Central Tendency & DispersionMTP Nov 20Question 3104 of 473
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If the relation between x\displaystyle x and y\displaystyle y is 5y−3x=10\displaystyle 5y - 3x = 10 and the mean deviation about mean for x\displaystyle x is 12\displaystyle 12, then the mean deviation of y\displaystyle y about mean is

Options

A9.20\displaystyle 9.20
B6.80\displaystyle 6.80
C7.20\displaystyle 7.20
D15.80\displaystyle 15.80
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Correct Answer

✅ Option c — 7.20\displaystyle 7.20

All Options:

  • A9.20\displaystyle 9.20
  • B6.80\displaystyle 6.80
  • C7.20\displaystyle 7.20
  • D15.80\displaystyle 15.80

Detailed Solution & Explanation

We are given the relationship between variables x\displaystyle x and y\displaystyle y: 5y−3x=10  ⟹  5y=3x+10  ⟹  y=0.6x+25y - 3x = 10 \implies 5y = 3x + 10 \implies y = 0.6x + 2 Since mean deviation is independent of change of origin but dependent on change of scale, for y=ax+b\displaystyle y = ax + b: M.D.y=∣a∣×M.D.x\text{M.D.}_y = |a| \times \text{M.D.}_x\n Substitute the given values (a=0.6\displaystyle a = 0.6 and M.D.x=12\displaystyle \text{M.D.}_x = 12): M.D.y=0.6×12=7.20\text{M.D.}_y = 0.6 \times 12 = 7.20 Hence, **Option C** is the correct answer.

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