Central Tendency & DispersionPYQ Sep 24Question 3147 of 473
All Questions

If each observation of a set is divided by 10, then the Standard Deviation of the new observation is:

Options

A110\displaystyle \frac{1}{10} of SD of original observation
B10th\displaystyle 10^{\text{th}} of SD of original observation
C100\displaystyle 100 of SD of original observation
D10\displaystyle 10 of SD of original observation
For any discrepancies in this question, email contact@cadada.in

Correct Answer

✅ Option a — 110\displaystyle \frac{1}{10} of SD of original observation

All Options:

  • A110\displaystyle \frac{1}{10} of SD of original observation
  • B10th\displaystyle 10^{\text{th}} of SD of original observation
  • C100\displaystyle 100 of SD of original observation
  • D10\displaystyle 10 of SD of original observation

Detailed Solution & Explanation

**Concept:** When every observation is multiplied (or divided) by a constant k\displaystyle k, the Standard Deviation is also multiplied (or divided) by ∣k∣\displaystyle |k|. **Proof:** If xi′=xi10\displaystyle x_i' = \frac{x_i}{10}, then xˉ′=xˉ10\displaystyle \bar{x}' = \frac{\bar{x}}{10}. σ′=∑(xi10−xˉ10)2n=∑(xi−xˉ10)2n=110∑(xi−xˉ)2n=σ10\sigma' = \sqrt{\frac{\sum\left(\frac{x_i}{10} - \frac{\bar{x}}{10}\right)^2}{n}} = \sqrt{\frac{\sum\left(\frac{x_i - \bar{x}}{10}\right)^2}{n}} = \frac{1}{10}\sqrt{\frac{\sum(x_i - \bar{x})^2}{n}} = \frac{\sigma}{10} Therefore, the new SD = 110\displaystyle \frac{1}{10} of the original SD. Hence, **Option A** is the correct answer.

More Questions from Central Tendency & Dispersion

Ready to Master Central Tendency & Dispersion?

Practice all 473 questions with instant feedback, earn XP, track your streaks, and ace your CA Foundation exam.

Start Practicing — It's Free