Central Tendency & DispersionMTP May 18Question 3149 of 473
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If the mean of frequency distribution is 100 and coefficient of variation is 45%\displaystyle 45\%, then Standard deviation is

Options

A45\displaystyle 45
B0.45\displaystyle 0.45
C4.5\displaystyle 4.5
D450\displaystyle 450
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Correct Answer

✅ Option a — 45\displaystyle 45

All Options:

  • A45\displaystyle 45
  • B0.45\displaystyle 0.45
  • C4.5\displaystyle 4.5
  • D450\displaystyle 450

Detailed Solution & Explanation

**Given:** Mean xˉ=100\displaystyle \bar{x} = 100, CV = 45% **Step 1: Use CV formula.** CV=σxˉ×100CV = \frac{\sigma}{\bar{x}} \times 100 45=σ100×10045 = \frac{\sigma}{100} \times 100 45=σ45 = \sigma **Result:** Standard Deviation = **45** Hence, **Option A** is the correct answer.

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