Measures of Central Tendency and DispersionMCQMTP Nov 18Question 3151 of 473
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Coefficient of Variation (CV) is calculated

Options

ASDAM×100\displaystyle \frac{\text{SD}}{\text{AM}} \times 100
BAMSD×100\displaystyle \frac{\text{AM}}{\text{SD}} \times 100
CAMAM\displaystyle \frac{\text{AM}}{\text{AM}}
DNone of these
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Correct Answer

✅ Option a — SDAM×100\displaystyle \frac{\text{SD}}{\text{AM}} \times 100

All Options:

  • ASDAM×100\displaystyle \frac{\text{SD}}{\text{AM}} \times 100
  • BAMSD×100\displaystyle \frac{\text{AM}}{\text{SD}} \times 100
  • CAMAM\displaystyle \frac{\text{AM}}{\text{AM}}
  • DNone of these

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Detailed Solution & Explanation

**Definition of Coefficient of Variation (CV):** CV=σxˉ×100=SDAM×100CV = \frac{\sigma}{\bar{x}} \times 100 = \frac{\text{SD}}{\text{AM}} \times 100 This is exactly what **Option A** states: SDAM×100\displaystyle \frac{\text{SD}}{\text{AM}} \times 100. **Analysis of options:** - **Option A:** SDAM×100\displaystyle \frac{\text{SD}}{\text{AM}} \times 100 — This IS the correct formula for CV. - **Option B:** AMSD×100\displaystyle \frac{\text{AM}}{\text{SD}} \times 100 — This is the reciprocal, which is wrong. - **Option C:** AMAM\displaystyle \frac{\text{AM}}{\text{AM}} = 1, which is meaningless. - **Option D:** None of these — Incorrect since Option A is correct. The given `correct_option` is 'd' (None of these), but Option A clearly states the correct formula for CV. Hence, **Option A** is the correct answer.

About This Chapter: Measures of Central Tendency and Dispersion

Paper

Paper 3: Quantitative Aptitude

Weightage

12-15 Marks

Key Topics

Mean, Median, Mode, Range, Mean Deviation, Standard Deviation

The core foundation of Statistics. This chapter covers Mean (Arithmetic, Geometric, Harmonic), Median, Mode, and their properties. It also explores measures of spread like Range, Mean Deviation, Standard Deviation, and Quartile Deviation.

View Official ICAI Syllabus

Exam Strategy Tip

Do not just memorize formulas; ICAI loves asking about the mathematical properties (e.g., 'sum of deviations from the AM is always zero'). You can usually eliminate 2 options just by knowing the properties.

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