Measures of Central Tendency and DispersionMCQICAI SM, MTP May 19 Series IIQuestion 3159 of 473
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If x\displaystyle x and y\displaystyle y are related by y=2x+5\displaystyle y = 2x + 5 and the SD and AM of x\displaystyle x are known to be 5\displaystyle 5 and 10\displaystyle 10 respectively, then the coefficient of variation of y\displaystyle y is

Options

A25\displaystyle 25
B30\displaystyle 30
C40\displaystyle 40
D20\displaystyle 20
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Correct Answer

Option c40\displaystyle 40

All Options:

  • A25\displaystyle 25
  • B30\displaystyle 30
  • C40\displaystyle 40
  • D20\displaystyle 20

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Detailed Solution & Explanation

**Given:** y=2x+5\displaystyle y = 2x + 5, SD(x)=5\displaystyle SD(x) = 5, AM(x)=xˉ=10\displaystyle AM(x) = \bar{x} = 10 **Step 1: Find SD of y\displaystyle y.** SD(y)=2×SD(x)=2×5=10SD(y) = |2| \times SD(x) = 2 \times 5 = 10 **Step 2: Find AM of y\displaystyle y.** yˉ=2xˉ+5=2(10)+5=25\bar{y} = 2\bar{x} + 5 = 2(10) + 5 = 25 **Step 3: Calculate CV of y\displaystyle y.** CV(y)=SD(y)yˉ×100=1025×100=40%CV(y) = \frac{SD(y)}{\bar{y}} \times 100 = \frac{10}{25} \times 100 = 40\% Wait — the answer is 40%, which is Option C. But the given `correct_option` is 'a' (25). Let me double-check: SD(y)=2×5=10\displaystyle SD(y) = 2 \times 5 = 10; yˉ=2(10)+5=25\displaystyle \bar{y} = 2(10)+5 = 25; CV=10/25×100=40\displaystyle CV = 10/25 \times 100 = 40. So Option C (40) is mathematically correct. Hence, **Option C** is the correct answer.

About This Chapter: Measures of Central Tendency and Dispersion

Paper

Paper 3: Quantitative Aptitude

Weightage

12-15 Marks

Key Topics

Mean, Median, Mode, Range, Mean Deviation, Standard Deviation

The core foundation of Statistics. This chapter covers Mean (Arithmetic, Geometric, Harmonic), Median, Mode, and their properties. It also explores measures of spread like Range, Mean Deviation, Standard Deviation, and Quartile Deviation.

View Official ICAI Syllabus

Exam Strategy Tip

Do not just memorize formulas; ICAI loves asking about the mathematical properties (e.g., 'sum of deviations from the AM is always zero'). You can usually eliminate 2 options just by knowing the properties.

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