The SD of a variable x is to be 10. SD of 50+5x is

Option a: 50. Solution: Given: SD(x) = 10 Find: SD(50 + 5x) Using the property: SD(a + bx) = |b| SD(x) Here a = 50, b = 5: SD(50 + 5x) = |5| x 10 = 50 The constant 50 does not affect SD; only the multiplier 5 matters. Hence, Option A is the correct answer.

The SD of a variable $x$ is to be 10. SD of $50+5x$ is

The correct answer is Option a: 50. **Given:** $SD(x) = 10$ **Find:** $SD(50 + 5x)$ **Using the property:** $SD(a + bx) = |b| \cdot SD(x)$ Here $a = 50$, $b = 5$: $$SD(50 + 5x) = |5| \times 10 = 50$$ The constant 50 does not affect SD; only the multiplier 5 matters. Hence, **Option A** is the correct answer.

Central Tendency & DispersionMTP June 22Question 3186 of 473

All Questions

The SD of a variable $\displaystyle x$ is to be 10. SD of $\displaystyle 50+5x$ is

Options

A50

B100

C10

D500

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Correct Answer

✅ Option a — 50

All Options:

A50
B100
C10
D500

Detailed Solution & Explanation

**Given:**

\displaystyle SD(x) = 10

**Find:**

\displaystyle SD(50 + 5x)

**Using the property:**

\displaystyle SD(a + bx) = |b| \cdot SD(x)

Here

\displaystyle a = 50

\displaystyle b = 5

SD(50 + 5x) = |5| \times 10 = 50

The constant 50 does not affect SD; only the multiplier 5 matters. Hence, **Option A** is the correct answer.

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The SD of a variable x\displaystyle xx is to be 10. SD of 50+5x\displaystyle 50+5x50+5x is