Central Tendency & DispersionPYQ June 23Question 3226 of 473
All Questions

For a given set of normally distributed data, the following statistical parameters are known: Mean =6\displaystyle = 6, Standard deviation =2.6\displaystyle = 2.6, Median =5\displaystyle = 5 and Quartile deviation =1.5\displaystyle = 1.5, then the coefficient of quartile deviation equals to

Options

A30\displaystyle 30
B32\displaystyle 32
C25\displaystyle 25
D39\displaystyle 39
For any discrepancies in this question, email contact@cadada.in

Correct Answer

✅ Option a — 30\displaystyle 30

All Options:

  • A30\displaystyle 30
  • B32\displaystyle 32
  • C25\displaystyle 25
  • D39\displaystyle 39

Detailed Solution & Explanation

We are given the parameters for a normal distribution: - Median = 5\displaystyle 5 - Quartile Deviation (Q.D.) = 1.5\displaystyle 1.5 The coefficient of quartile deviation is defined as: Coefficient of Q.D.=Q.D.Median×100\text{Coefficient of Q.D.} = \frac{\text{Q.D.}}{\text{Median}} \times 100 Coefficient of Q.D.=1.55×100=30%\text{Coefficient of Q.D.} = \frac{1.5}{5} \times 100 = 30\% Hence, **Option A** is the correct answer.

More Questions from Central Tendency & Dispersion

Ready to Master Central Tendency & Dispersion?

Practice all 473 questions with instant feedback, earn XP, track your streaks, and ace your CA Foundation exam.

Start Practicing — It's Free