If Quartile deviation is 7. Find the value of x from the arranged series: 2, x, 6, 7, 9, 16, 18.

Option b: 2. Solution: We are given an arranged series: 2, x, 6, 7, 9, 16, 18 with n = 7. - The first quartile (Q1) is the second value: Q1 = x. - The third quartile (Q3) is the sixth value: Q3 = 16. - Quartile deviation (Q.D.) = 7. Set up the quartile deviation equation: text{Q.D.} = Q3 - Q1/2 implies 7 = 16 - x/2 14 = 16 - x implies x = 2 Hence, Option B is the correct answer.

If Quartile deviation is $7$. Find the value of $x$ from the arranged series: $2, x, 6, 7, 9, 16, 18$.

The correct answer is Option b: $2$. We are given an arranged series: $2, x, 6, 7, 9, 16, 18$ with $n = 7$. - The first quartile ($Q_1$) is the second value: $Q_1 = x$. - The third quartile ($Q_3$) is the sixth value: $Q_3 = 16$. - Quartile deviation (Q.D.) = $7$. Set up the quartile deviation equation: $$\text{Q.D.} = \frac{Q_3 - Q_1}{2} \implies 7 = \frac{16 - x}{2}$$ $$14 = 16 - x \\implies x = 2$$ Hence, **Option B** is the correct answer.

Central Tendency & DispersionMTP Dec 23 - Series IQuestion 3259 of 473

All Questions

If Quartile deviation is $\displaystyle 7$ . Find the value of $\displaystyle x$ from the arranged series: $\displaystyle 2, x, 6, 7, 9, 16, 18$ .

Options

\displaystyle 5

\displaystyle 2

\displaystyle 8

\displaystyle 6

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Correct Answer

✅ Option b — $\displaystyle 2$

All Options:

A $\displaystyle 5$
B $\displaystyle 2$
C $\displaystyle 8$
D $\displaystyle 6$

Detailed Solution & Explanation

We are given an arranged series:

\displaystyle 2, x, 6, 7, 9, 16, 18

with

\displaystyle n = 7

. - The first quartile (

\displaystyle Q_1

) is the second value:

\displaystyle Q_1 = x

. - The third quartile (

\displaystyle Q_3

) is the sixth value:

\displaystyle Q_3 = 16

. - Quartile deviation (Q.D.) =

\displaystyle 7

. Set up the quartile deviation equation:

\text{Q.D.} = \frac{Q_3 - Q_1}{2} \implies 7 = \frac{16 - x}{2}

14 = 16 - x \\implies x = 2

Hence, **Option B** is the correct answer.

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If Quartile deviation is 7\displaystyle 77. Find the value of x\displaystyle xx from the arranged series: 2,x,6,7,9,16,18\displaystyle 2, x, 6, 7, 9, 16, 182,x,6,7,9,16,18.