Central Tendency & DispersionMTP Dec 23 - Series IQuestion 3260 of 473
All Questions

If the first quartile is 142\displaystyle 142 and semi-inter quartile range is 18\displaystyle 18, then the value of median is:

Options

A151\displaystyle 151
B160\displaystyle 160
C178\displaystyle 178
DNone of these
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Correct Answer

✅ Option b — 160\displaystyle 160

All Options:

  • A151\displaystyle 151
  • B160\displaystyle 160
  • C178\displaystyle 178
  • DNone of these

Detailed Solution & Explanation

We are given: - First quartile: Q1=142\displaystyle Q_1 = 142 - Semi-interquartile range (Q.D.) = 18\displaystyle 18 For a symmetric distribution, the median lies exactly halfway between Q1\displaystyle Q_1 and Q3\displaystyle Q_3: Median=Q1+Q.D.=142+18=160\text{Median} = Q_1 + \text{Q.D.} = 142 + 18 = 160 Hence, **Option B** is the correct answer.

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