ProbabilityMCQMTP Dec 22 Series IIQuestion 3299 of 187
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The probability that a leap year has 53\displaystyle 53 Wednesday is:

Options

A27\displaystyle \frac{2}{7}
B35\displaystyle \frac{3}{5}
C17\displaystyle \frac{1}{7}
D23\displaystyle \frac{2}{3}
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Correct Answer

✅ Option a — 27\displaystyle \frac{2}{7}

All Options:

  • A27\displaystyle \frac{2}{7}
  • B35\displaystyle \frac{3}{5}
  • C17\displaystyle \frac{1}{7}
  • D23\displaystyle \frac{2}{3}

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Detailed Solution & Explanation

**Probability of 53 Wednesdays in a Leap Year (Repeated)** A leap year has 366 days = 52 weeks + 2 extra days. The 7 possible pairs of extra days: (Sun,Mon), (Mon,Tue), (Tue,Wed), (Wed,Thu), (Thu,Fri), (Fri,Sat), (Sat,Sun)(Sun,Mon),\ (Mon,Tue),\ (Tue,Wed),\ (Wed,Thu),\ (Thu,Fri),\ (Fri,Sat),\ (Sat,Sun) Pairs containing Wednesday: - (Tue,Wed)\displaystyle (Tue, Wed) - (Wed,Thu)\displaystyle (Wed, Thu) Favorable = 2, Total = 7 P(53 Wednesdays)=27P(53 \text{ Wednesdays}) = \frac{2}{7} Hence, **Option A** is the correct answer.

About This Chapter: Probability

Paper

Paper 3: Quantitative Aptitude

Weightage

5-7 Marks

Key Topics

Probability Operations, Expected Value

A logic-heavy chapter dealing with random experiments, events (mutually exclusive, exhaustive), set theory probability, conditional probability, and Bayes' Theorem. It forms the basis for Theoretical Distributions.

View Official ICAI Syllabus

Exam Strategy Tip

Always draw a quick Venn Diagram or tree when faced with 'At least one' or 'Only A but not B' wording. It saves you from double-counting.

Key Concepts to Understand

Probability

A numerical measure of the likelihood of an event occurring, expressed as a number between 0 (impossible) and 1 (certain). Formula: P(A) = Number of favorable outcomes / Total number of equally likely outcomes.

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