ProbabilityMCQMTP Nov 20Question 3378 of 187
All Questions

What is the probability that a leap year selected at random contains either 53\displaystyle 53 Sundays or 53\displaystyle 53 Mondays.

Options

A27\displaystyle \frac{2}{7}
B37\displaystyle \frac{3}{7}
C47\displaystyle \frac{4}{7}
D17\displaystyle \frac{1}{7}
For any discrepancies in this question, email contact@cadada.in

Correct Answer

Option b37\displaystyle \frac{3}{7}

All Options:

  • A27\displaystyle \frac{2}{7}
  • B37\displaystyle \frac{3}{7}
  • C47\displaystyle \frac{4}{7}
  • D17\displaystyle \frac{1}{7}

Ad

Detailed Solution & Explanation

**Probability of 53 Sundays or 53 Mondays in a Leap Year** A leap year contains 366 days, which is equal to 52 weeks and 2 extra days. The 2 extra days can form any of the following 7 pairs of consecutive days: 1. (Sunday, Monday) 2. (Monday, Tuesday) 3. (Tuesday, Wednesday) 4. (Wednesday, Thursday) 5. (Thursday, Friday) 6. (Friday, Saturday) 7. (Saturday, Sunday) Let S\displaystyle S be the event that the leap year has 53 Sundays (extra days contain Sunday). S={(Saturday, Sunday),(Sunday, Monday)}S = \{(\text{Saturday, Sunday}), (\text{Sunday, Monday})\} Let M\displaystyle M be the event that the leap year has 53 Mondays (extra days contain Monday). M={(Sunday, Monday),(Monday, Tuesday)}M = \{(\text{Sunday, Monday}), (\text{Monday, Tuesday})\} The event "53 Sundays or 53 Mondays" is SM\displaystyle S \cup M: SM={(Saturday, Sunday),(Sunday, Monday),(Monday, Tuesday)}S \cup M = \{(\text{Saturday, Sunday}), (\text{Sunday, Monday}), (\text{Monday, Tuesday})\} There are exactly 3 favorable pairs out of 7 possible pairs. Thus, the probability is: P(SM)=37P(S \cup M) = \frac{3}{7} Hence, **Option B** is the correct answer.

About This Chapter: Probability

Paper

Paper 3: Quantitative Aptitude

Weightage

5-7 Marks

Key Topics

Probability Operations, Expected Value

A logic-heavy chapter dealing with random experiments, events (mutually exclusive, exhaustive), set theory probability, conditional probability, and Bayes' Theorem. It forms the basis for Theoretical Distributions.

View Official ICAI Syllabus

Exam Strategy Tip

Always draw a quick Venn Diagram or tree when faced with 'At least one' or 'Only A but not B' wording. It saves you from double-counting.

Key Concepts to Understand

More Questions from Probability

Ready to Master Probability?

Practice all 187 questions with instant feedback, earn XP, track your streaks, and ace your CA Foundation exam.

Start Practicing — It's Free