ProbabilityMCQMTP Apr 21Question 3381 of 187
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A bag contains 12\displaystyle 12 balls of which 3\displaystyle 3 are red and 5\displaystyle 5 balls are drawn at random. Find the probability that 3\displaystyle 3 balls are red.

Options

A3132\displaystyle \frac{3}{132}
B5396\displaystyle \frac{5}{396}
C136\displaystyle \frac{1}{36}
D122\displaystyle \frac{1}{22}
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Correct Answer

Option d122\displaystyle \frac{1}{22}

All Options:

  • A3132\displaystyle \frac{3}{132}
  • B5396\displaystyle \frac{5}{396}
  • C136\displaystyle \frac{1}{36}
  • D122\displaystyle \frac{1}{22}

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Detailed Solution & Explanation

**Probability of Drawing 3 Red Balls Out of 5** Total balls in the bag = 12 - Red balls = 3 - Non-red balls = 9 Five balls are drawn at random. We want to find the probability that exactly 3 of the drawn balls are red. **Step 1: Calculate total ways to draw 5 balls** Total ways=(125)=12×11×10×9×85×4×3×2×1=792\text{Total ways} = \binom{12}{5} = \frac{12 \times 11 \times 10 \times 9 \times 8}{5 \times 4 \times 3 \times 2 \times 1} = 792 **Step 2: Calculate favorable ways** To get exactly 3 red balls, we must choose all 3 red balls and 2 non-red balls: Favorable ways=(33)×(92)=1×9×82=36\text{Favorable ways} = \binom{3}{3} \times \binom{9}{2} = 1 \times \frac{9 \times 8}{2} = 36 **Step 3: Probability calculation** P=36792=122P = \frac{36}{792} = \frac{1}{22} Hence, **Option D** is the correct answer.

About This Chapter: Probability

Paper

Paper 3: Quantitative Aptitude

Weightage

5-7 Marks

Key Topics

Probability Operations, Expected Value

A logic-heavy chapter dealing with random experiments, events (mutually exclusive, exhaustive), set theory probability, conditional probability, and Bayes' Theorem. It forms the basis for Theoretical Distributions.

View Official ICAI Syllabus

Exam Strategy Tip

Always draw a quick Venn Diagram or tree when faced with 'At least one' or 'Only A but not B' wording. It saves you from double-counting.

Key Concepts to Understand

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