Theoretical DistributionsMCQPYQ Nov 18Question 3417 of 230
All Questions

The probability that a student is not a swimmer is 1/5\displaystyle 1/5 then the probability that out of five students four are swimmer is

Options

A5C1(15)1(45)4\displaystyle ^5C_1 \left(\frac{1}{5}\right)^1 \left(\frac{4}{5}\right)^4
B5C1(45)1(15)4\displaystyle ^5C_1 \left(\frac{4}{5}\right)^1 \left(\frac{1}{5}\right)^4
C5C4(45)4(15)1\displaystyle ^5C_4 \left(\frac{4}{5}\right)^4 \left(\frac{1}{5}\right)^1
DNone of the above
For any discrepancies in this question, email contact@cadada.in

Correct Answer

Option c5C4(45)4(15)1\displaystyle ^5C_4 \left(\frac{4}{5}\right)^4 \left(\frac{1}{5}\right)^1

All Options:

  • A5C1(15)1(45)4\displaystyle ^5C_1 \left(\frac{1}{5}\right)^1 \left(\frac{4}{5}\right)^4
  • B5C1(45)1(15)4\displaystyle ^5C_1 \left(\frac{4}{5}\right)^1 \left(\frac{1}{5}\right)^4
  • C5C4(45)4(15)1\displaystyle ^5C_4 \left(\frac{4}{5}\right)^4 \left(\frac{1}{5}\right)^1
  • DNone of the above

Ad

Detailed Solution & Explanation

**Probability of Exactly 4 Swimmers out of 5 Students** **Given:** - P(not a swimmer)=frac15\displaystyle P(\text{not a swimmer}) = \\frac{1}{5}, so q=frac15\displaystyle q = \\frac{1}{5} - P(swimmer)=1frac15=frac45\displaystyle P(\text{swimmer}) = 1 - \\frac{1}{5} = \\frac{4}{5}, so p=frac45\displaystyle p = \\frac{4}{5} - n=5\displaystyle n = 5 students, we want exactly r=4\displaystyle r = 4 swimmers **Using Binomial Probability Formula:** P(X=r)=(nr)prqnrP(X = r) = \binom{n}{r} p^r q^{n-r} P(X=4)=(54)(frac45)4(frac15)54P(X = 4) = \binom{5}{4} \left(\\frac{4}{5}\right)^4 \left(\\frac{1}{5}\right)^{5-4} =5C4(frac45)4(frac15)1= {}^5C_4 \left(\\frac{4}{5}\right)^4 \left(\\frac{1}{5}\right)^1 **Checking the options:** - **Option A:** 5C1(frac15)1(frac45)4\displaystyle {}^5C_1 \left(\\frac{1}{5}\right)^1 \left(\\frac{4}{5}\right)^4 — This uses 5C1\displaystyle {}^5C_1 instead of 5C4\displaystyle {}^5C_4. Note 5C1=5C4=5\displaystyle {}^5C_1 = {}^5C_4 = 5, so numerically equal, but the expression is set up conceptually wrong (selecting 1 non-swimmer vs. 4 swimmers). The standard form for selecting 4 swimmers is 5C4\displaystyle {}^5C_4. - **Option B:** Wrong powers assigned — p\displaystyle p and q\displaystyle q swapped incorrectly. - **Option C:** 5C4(frac45)4(frac15)1\displaystyle {}^5C_4 \left(\\frac{4}{5}\right)^4 \left(\\frac{1}{5}\right)^1 — This is **exactly** the binomial formula: choosing 4 swimmers from 5, each swimmer has probability frac45\displaystyle \\frac{4}{5}, and the remaining 1 student is not a swimmer with probability frac15\displaystyle \\frac{1}{5}. ✓ Hence, **Option C** is the correct answer.

About This Chapter: Theoretical Distributions

Paper

Paper 3: Quantitative Aptitude

Weightage

4-6 Marks

Key Topics

Binomial, Poisson, Normal Distribution

This chapter covers Binomial, Poisson, Normal Distribution and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 4-6 Marks weightage. Focus on understanding core concepts rather than memorizing.

Key Concepts to Understand

More Questions from Theoretical Distributions

Ready to Master Theoretical Distributions?

Practice all 230 questions with instant feedback, earn XP, track your streaks, and ace your CA Foundation exam.

Start Practicing — It's Free