Theoretical DistributionsMCQPYQ Jan 21Question 3422 of 230
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A coin with probability for heads as 1/5\displaystyle 1/5 is tossed 100\displaystyle 100 times. The standard deviation of the number of head 5\displaystyle 5 turned up is.

Options

A3\displaystyle 3
B2\displaystyle 2
C4\displaystyle 4
D6\displaystyle 6
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Correct Answer

Option c4\displaystyle 4

All Options:

  • A3\displaystyle 3
  • B2\displaystyle 2
  • C4\displaystyle 4
  • D6\displaystyle 6

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Detailed Solution & Explanation

**Standard Deviation of Number of Heads** **Given:** - n=100\displaystyle n = 100 tosses - p=P(head)=frac15\displaystyle p = P(\text{head}) = \\frac{1}{5} - q=1p=1frac15=frac45\displaystyle q = 1 - p = 1 - \\frac{1}{5} = \\frac{4}{5} **Step 1: Calculate the Variance** Variance=npq=100×frac15×frac45\text{Variance} = npq = 100 \times \\frac{1}{5} \times \\frac{4}{5} =100×frac425=frac40025=16= 100 \times \\frac{4}{25} = \\frac{400}{25} = 16 **Step 2: Calculate the Standard Deviation** SD=sqrtVariance=sqrt16=4\text{SD} = \\sqrt{\text{Variance}} = \\sqrt{16} = 4 **Checking the options:** - Option A: 3\displaystyle 3 ✗ - Option B: 2\displaystyle 2 ✗ - **Option C: 4\displaystyle 4** ✓ - Option D: 6\displaystyle 6 ✗ **Summary:** Mean=np=100×frac15=20\text{Mean} = np = 100 \times \\frac{1}{5} = 20 Variance=npq=100×frac15×frac45=16\text{Variance} = npq = 100 \times \\frac{1}{5} \times \\frac{4}{5} = 16 Standard Deviation=sqrt16=4\text{Standard Deviation} = \\sqrt{16} = 4 Hence, **Option C** is the correct answer.

About This Chapter: Theoretical Distributions

Paper

Paper 3: Quantitative Aptitude

Weightage

4-6 Marks

Key Topics

Binomial, Poisson, Normal Distribution

This chapter covers Binomial, Poisson, Normal Distribution and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 4-6 Marks weightage. Focus on understanding core concepts rather than memorizing.

Key Concepts to Understand

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