Theoretical DistributionsMTP Nov 18Question 3564 of 221
All Questions

If X is normal variate with mean 6 and variance 16 then the value of the probability. P(2X10)\displaystyle P(2 \le X \le 10) is equal to.

Options

A2P(0X10)\displaystyle 2P(0 \le X \le 10)
B2P(6X10)\displaystyle 2P(6 \le X \le 10)
CP(0X6)\displaystyle P(0 \le X \le 6)
DP(0X10)\displaystyle P(0 \le X \le 10)
For any discrepancies in this question, email contact@cadada.in

Correct Answer

Option a2P(0X10)\displaystyle 2P(0 \le X \le 10)

All Options:

  • A2P(0X10)\displaystyle 2P(0 \le X \le 10)
  • B2P(6X10)\displaystyle 2P(6 \le X \le 10)
  • CP(0X6)\displaystyle P(0 \le X \le 6)
  • DP(0X10)\displaystyle P(0 \le X \le 10)

About This Chapter: Theoretical Distributions

Paper

Paper 3: Quantitative Aptitude

Weightage

4-6 Marks

Key Topics

Binomial, Poisson, Normal Distribution

This chapter covers Binomial, Poisson, Normal Distribution and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 4-6 Marks weightage. Focus on understanding core concepts rather than memorizing.

More Questions from Theoretical Distributions

Ready to Master Theoretical Distributions?

Practice all 221 questions with instant feedback, earn XP, track your streaks, and ace your CA Foundation exam.

Start Practicing — It's Free