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If ₹ 58 is divided among 150 children such that each girl and each boy gets 25 p and 50 p respectively. Then how many girls are there?

Options

A52
B54
C68
D62
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Correct Answer

Option c68

All Options:

  • A52
  • B54
  • C68
  • D62

Detailed Solution & Explanation

Let the number of girls be represented by g\displaystyle g and the number of boys by b\displaystyle b.
The total number of children is 150\displaystyle 150:
g+b=150    b=150g— (Equation 1)g + b = 150 \implies b = 150 - g \quad \text{--- (Equation 1)}
The total amount divided is 58\displaystyle ₹ 58. Since the individual amounts are given in paise, we convert the total amount into paise:
Total amount=58×100=5800 paise\text{Total amount} = 58 \times 100 = 5800 \text{ paise}
Each girl gets 25 p\displaystyle 25\text{ p} and each boy gets 50 p\displaystyle 50\text{ p}. Therefore, we can write the equation for the total amount:
25g+50b=5800— (Equation 2)25g + 50b = 5800 \quad \text{--- (Equation 2)}
Substitute Equation 1 into Equation 2:
25g+50(150g)=580025g + 50(150 - g) = 5800
Expand the equation:
25g+750050g=580025g + 7500 - 50g = 5800
Combine the terms involving g\displaystyle g:
25g+7500=5800-25g + 7500 = 5800
Rearrange the terms to solve for g\displaystyle g:
25g=7500580025g = 7500 - 5800
25g=170025g = 1700
g=170025=68g = \frac{1700}{25} = 68
Thus, there are 68\displaystyle 68 girls.
Hence, **Option C** is the correct answer.

About This Chapter: Equations

Paper

Paper 3: Quantitative Aptitude

Weightage

4-6 Marks

Key Topics

Linear, Quadratic and Cubic Equations

This chapter covers Linear, Quadratic and Cubic Equations and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 4-6 Marks weightage. Focus on understanding core concepts rather than memorizing.

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