EquationsPYQ May 25Question 4006 of 155
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The quadratic equation 2x25x+1=0\displaystyle 2x^2 - \sqrt{5}x + 1 = 0 has

Options

ATwo distinct real roots
BTwo equal real roots
CNo real roots
DMore than two real roots
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Correct Answer

Option cNo real roots

All Options:

  • ATwo distinct real roots
  • BTwo equal real roots
  • CNo real roots
  • DMore than two real roots

Detailed Solution & Explanation

For a quadratic equation of the form ax2+bx+c=0\displaystyle ax^2 + bx + c = 0, the nature of the roots is determined by its discriminant, denoted by Δ\displaystyle \Delta or D\displaystyle D:
D=b24acD = b^2 - 4ac
In the given equation, 2x25x+1=0\displaystyle 2x^2 - \sqrt{5}x + 1 = 0, we identify the coefficients:
a=2,b=5,c=1a = 2, \quad b = -\sqrt{5}, \quad c = 1
Now, calculate the discriminant:
D=(5)24×2×1D = (-\sqrt{5})^2 - 4 \times 2 \times 1
D=58D = 5 - 8
D=3D = -3
Since the discriminant is negative (D<0\displaystyle D < 0), the quadratic equation has no real roots (the roots are imaginary/complex numbers).
Hence, **Option C** is the correct answer.

About This Chapter: Equations

Paper

Paper 3: Quantitative Aptitude

Weightage

4-6 Marks

Key Topics

Linear, Quadratic and Cubic Equations

This chapter covers Linear, Quadratic and Cubic Equations and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 4-6 Marks weightage. Focus on understanding core concepts rather than memorizing.

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