If thrice of A's age 6 years ago be subtracted from twice his present age, the result would be equal to his present age. Find A's present age.
Correct Answer
✅ Option c — 9
All Options:
- A7
- B8
- C9
- D6
Detailed Solution & Explanation
A's age 6 years ago was years.
According to the problem, thrice of A's age 6 years ago, $3(x-6)$, is subtracted from twice his present age, $2x$, resulting in his present age, :
Let's solve for :
Therefore, A's present age is 9 years.
**Correct Option: (c)**
About This Chapter: Equations
Paper
Paper 3: Quantitative Aptitude
Weightage
4-6 Marks
Key Topics
Linear, Quadratic and Cubic Equations
This chapter covers Linear, Quadratic and Cubic Equations and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.
View Official ICAI SyllabusExam Strategy Tip
This topic carries 4-6 Marks weightage. Focus on understanding core concepts rather than memorizing.
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