Number Series, Coding and DecodingMCQMTP Dec 2023 Series IQuestion 2073 of 217
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Find next number of the series $7, 23, 47, 119, 167$

Select Your Answer (Keyboard: A, B, C, D)
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Correct Answer

✅ Option c — $287$

All Options:

  • A$211$
  • B$223$
  • C$287$
  • D$319$

Detailed Solution & Explanation

To find the next number in the series $7, 23, 47, 119, 167, ?,letusanalyzeeachterm′srelationshiptoperfectsquares:<br><br>Let\displaystyle , let us analyze each term's relationship to perfect squares:<br><br>LetT_nrepresentthe\displaystyle represent then−thterm.Wecanexpresseachtermusingtheformula:<br><spanclass="katex−display"><spanclass="katex"><spanclass="katex−mathml"><mathxmlns="http://www.w3.org/1998/Math/MathML"display="block"><semantics><mrow><msub><mi>T</mi><mi>n</mi></msub><mo>=</mo><mostretchy="false">(</mo><msub><mi>p</mi><mi>n</mi></msub><msup><mostretchy="false">)</mo><mn>2</mn></msup><mo>−</mo><mn>2</mn></mrow><annotationencoding="application/x−tex">Tn=(pn)2−2</annotation></semantics></math></span><spanclass="katex−html"aria−hidden="true"><spanclass="base"><spanclass="strut"style="height:0.8333em;vertical−align:−0.15em;"></span><spanclass="mord"><spanclass="mordmathnormal"style="margin−right:0.13889em;">T</span><spanclass="msupsub"><spanclass="vlist−tvlist−t2"><spanclass="vlist−r"><spanclass="vlist"style="height:0.1514em;"><spanstyle="top:−2.55em;margin−left:−0.1389em;margin−right:0.05em;"><spanclass="pstrut"style="height:2.7em;"></span><spanclass="sizingreset−size6size3mtight"><spanclass="mordmathnormalmtight">n</span></span></span></span><spanclass="vlist−s">​</span></span><spanclass="vlist−r"><spanclass="vlist"style="height:0.15em;"><span></span></span></span></span></span></span><spanclass="mspace"style="margin−right:0.2778em;"></span><spanclass="mrel">=</span><spanclass="mspace"style="margin−right:0.2778em;"></span></span><spanclass="base"><spanclass="strut"style="height:1.1141em;vertical−align:−0.25em;"></span><spanclass="mopen">(</span><spanclass="mord"><spanclass="mordmathnormal">p</span><spanclass="msupsub"><spanclass="vlist−tvlist−t2"><spanclass="vlist−r"><spanclass="vlist"style="height:0.1514em;"><spanstyle="top:−2.55em;margin−left:0em;margin−right:0.05em;"><spanclass="pstrut"style="height:2.7em;"></span><spanclass="sizingreset−size6size3mtight"><spanclass="mordmathnormalmtight">n</span></span></span></span><spanclass="vlist−s">​</span></span><spanclass="vlist−r"><spanclass="vlist"style="height:0.15em;"><span></span></span></span></span></span></span><spanclass="mclose"><spanclass="mclose">)</span><spanclass="msupsub"><spanclass="vlist−t"><spanclass="vlist−r"><spanclass="vlist"style="height:0.8641em;"><spanstyle="top:−3.113em;margin−right:0.05em;"><spanclass="pstrut"style="height:2.7em;"></span><spanclass="sizingreset−size6size3mtight"><spanclass="mordmtight">2</span></span></span></span></span></span></span></span><spanclass="mspace"style="margin−right:0.2222em;"></span><spanclass="mbin">−</span><spanclass="mspace"style="margin−right:0.2222em;"></span></span><spanclass="base"><spanclass="strut"style="height:0.6444em;"></span><spanclass="mord">2</span></span></span></span></span><br>where\displaystyle -th term. We can express each term using the formula:<br><span class="katex-display"><span class="katex"><span class="katex-mathml"><math xmlns="http://www.w3.org/1998/Math/MathML" display="block"><semantics><mrow><msub><mi>T</mi><mi>n</mi></msub><mo>=</mo><mo stretchy="false">(</mo><msub><mi>p</mi><mi>n</mi></msub><msup><mo stretchy="false">)</mo><mn>2</mn></msup><mo>−</mo><mn>2</mn></mrow><annotation encoding="application/x-tex">T_n = (p_n)^2 - 2</annotation></semantics></math></span><span class="katex-html" aria-hidden="true"><span class="base"><span class="strut" style="height:0.8333em;vertical-align:-0.15em;"></span><span class="mord"><span class="mord mathnormal" style="margin-right:0.13889em;">T</span><span class="msupsub"><span class="vlist-t vlist-t2"><span class="vlist-r"><span class="vlist" style="height:0.1514em;"><span style="top:-2.55em;margin-left:-0.1389em;margin-right:0.05em;"><span class="pstrut" style="height:2.7em;"></span><span class="sizing reset-size6 size3 mtight"><span class="mord mathnormal mtight">n</span></span></span></span><span class="vlist-s">​</span></span><span class="vlist-r"><span class="vlist" style="height:0.15em;"><span></span></span></span></span></span></span><span class="mspace" style="margin-right:0.2778em;"></span><span class="mrel">=</span><span class="mspace" style="margin-right:0.2778em;"></span></span><span class="base"><span class="strut" style="height:1.1141em;vertical-align:-0.25em;"></span><span class="mopen">(</span><span class="mord"><span class="mord mathnormal">p</span><span class="msupsub"><span class="vlist-t vlist-t2"><span class="vlist-r"><span class="vlist" style="height:0.1514em;"><span style="top:-2.55em;margin-left:0em;margin-right:0.05em;"><span class="pstrut" style="height:2.7em;"></span><span class="sizing reset-size6 size3 mtight"><span class="mord mathnormal mtight">n</span></span></span></span><span class="vlist-s">​</span></span><span class="vlist-r"><span class="vlist" style="height:0.15em;"><span></span></span></span></span></span></span><span class="mclose"><span class="mclose">)</span><span class="msupsub"><span class="vlist-t"><span class="vlist-r"><span class="vlist" style="height:0.8641em;"><span style="top:-3.113em;margin-right:0.05em;"><span class="pstrut" style="height:2.7em;"></span><span class="sizing reset-size6 size3 mtight"><span class="mord mtight">2</span></span></span></span></span></span></span></span><span class="mspace" style="margin-right:0.2222em;"></span><span class="mbin">−</span><span class="mspace" style="margin-right:0.2222em;"></span></span><span class="base"><span class="strut" style="height:0.6444em;"></span><span class="mord">2</span></span></span></span></span><br>wherep_n$ represents the sequence of consecutive prime numbers starting from $3\displaystyle (&#36;3, 5, 7, 11, 13, \dots). Note that 9\displaystyle 9 is omitted because it is a composite number, not a prime number.

Let us compute the terms to verify this pattern:
- 1st term (p1=3\displaystyle p_1 = 3): 32−2=9−2=7\displaystyle 3^2 - 2 = 9 - 2 = 7
- 2nd term (p2=5\displaystyle p_2 = 5): 52−2=25−2=23\displaystyle 5^2 - 2 = 25 - 2 = 23
- 3rd term (p3=7\displaystyle p_3 = 7): 72−2=49−2=47\displaystyle 7^2 - 2 = 49 - 2 = 47
- 4th term (p4=11\displaystyle p_4 = 11): $11^2 - 2 = 121 - 2 = 119<br>−5thterm(\displaystyle <br>- 5th term (p_5 = 13\displaystyle ): &#36;13^2 - 2 = 169 - 2 = 167

Following this logical progression, the next prime number after $13\displaystyle is &#36;17. Therefore, the 6th term must be:
- 6th term (p6=17\displaystyle p_6 = 17): $17^2 - 2 = 289 - 2 = 287\displaystyle <br><br>This mathematical proof uniquely demonstrates that the next term in the series is **&#36;287**, which corresponds to **Option C**.

*Note on Answer Key Discrepancy:* The textbook/exam answer key lists **Option A** ($211$) as the correct answer. However, $211$ does not correspond to any logical progression or prime square pattern, whereas $287$ fits the consecutive prime-squared minus two formula perfectly. This is a clear typographical error in the official answer key, and the correct option is **Option C**.

Hence, **Option C** is the correct answer.

About This Chapter: Number Series, Coding and Decoding

Paper

Paper 3: Quantitative Aptitude

Weightage

5 Marks

Key Topics

Number series, Coding & Decoding, Odd man out

This chapter covers Number series, Coding & Decoding, Odd man out and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 5 Marks weightage. Focus on understanding core concepts rather than memorizing.

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