Number Series, Coding and DecodingMCQPYQ Sep 24Question 2106 of 217
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In a certain code INACTIVE is written as VITCANIE, How is COMPUTER written in the same code

Select Your Answer (Keyboard: A, B, C, D)
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Correct Answer

✅ Option b — ETUPMOCR

All Options:

  • APMOCRETU
  • BETUPMOCR
  • CUTEPMOCU
  • DMOCPETUR

Detailed Solution & Explanation

Let's analyze the pattern by mapping the positions of the letters in INACTIVE\displaystyle INACTIVE (length 8\displaystyle 8) to its coded form VITCANIE\displaystyle VITCANIE:
Let the positions in the original word be numbered 1\displaystyle 1 to 8\displaystyle 8:
I1N2A3C4T5I6V7E8\displaystyle I1\displaystyle \text{I}_1 N2\displaystyle \text{N}_2 A3\displaystyle \text{A}_3 C4\displaystyle \text{C}_4 T5\displaystyle \text{T}_5 I6\displaystyle \text{I}_6 V7\displaystyle \text{V}_7 E8\displaystyle \text{E}_8

The coded word VITCANIE\displaystyle VITCANIE has the following letters:
V7I6T5C4A3N2I1E8\displaystyle V7\displaystyle \text{V}_7 I6\displaystyle \text{I}_6 T5\displaystyle \text{T}_5 C4\displaystyle \text{C}_4 A3\displaystyle \text{A}_3 N2\displaystyle \text{N}_2 I1\displaystyle \text{I}_1 E8\displaystyle \text{E}_8

From this, we observe that:
1. The first 7\displaystyle 7 letters (I1N2A3C4T5I6V7\displaystyle I1\displaystyle \text{I}_1 N2\displaystyle \text{N}_2 A3\displaystyle \text{A}_3 C4\displaystyle \text{C}_4 T5\displaystyle \text{T}_5 I6\displaystyle \text{I}_6 V7\displaystyle \text{V}_7) are reversed to become V7I6T5C4A3N2I1\displaystyle V7\displaystyle \text{V}_7 I6\displaystyle \text{I}_6 T5\displaystyle \text{T}_5 C4\displaystyle \text{C}_4 A3\displaystyle \text{A}_3 N2\displaystyle \text{N}_2 I1\displaystyle \text{I}_1.
2. The last letter (E8\displaystyle E8\displaystyle \text{E}_8) remains in its original position at the end.

Now, let's apply the same pattern to the word COMPUTER\displaystyle COMPUTER (length 8\displaystyle 8):
Original positions: C1O2M3P4U5T6E7R8\displaystyle C1\displaystyle \text{C}_1 O2\displaystyle \text{O}_2 M3\displaystyle \text{M}_3 P4\displaystyle \text{P}_4 U5\displaystyle \text{U}_5 T6\displaystyle \text{T}_6 E7\displaystyle \text{E}_7 R8\displaystyle \text{R}_8

1. Reverse the first 7\displaystyle 7 letters (C1O2M3P4U5T6E7\displaystyle C1\displaystyle \text{C}_1 O2\displaystyle \text{O}_2 M3\displaystyle \text{M}_3 P4\displaystyle \text{P}_4 U5\displaystyle \text{U}_5 T6\displaystyle \text{T}_6 E7\displaystyle \text{E}_7):
E7T6U5P4M3O2C1\displaystyle E7\displaystyle \text{E}_7 T6\displaystyle \text{T}_6 U5\displaystyle \text{U}_5 P4\displaystyle \text{P}_4 M3\displaystyle \text{M}_3 O2\displaystyle \text{O}_2 C1\displaystyle \text{C}_1
2. Keep the last letter (R8\displaystyle R8\displaystyle \text{R}_8) at the end:
R8\displaystyle R8\displaystyle \text{R}_8

Combining these, we get ETUPMOCR\displaystyle ETUPMOCR.

Hence, **Option B** is the correct answer.

About This Chapter: Number Series, Coding and Decoding

Paper

Paper 3: Quantitative Aptitude

Weightage

5 Marks

Key Topics

Number series, Coding & Decoding, Odd man out

This chapter covers Number series, Coding & Decoding, Odd man out and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 5 Marks weightage. Focus on understanding core concepts rather than memorizing.

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