Number Series, Coding and DecodingMCQMTP Sep 24 Series IQuestion 2154 of 217
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If E=6\displaystyle E = 6, MAT=34\displaystyle MAT = 34, then how much is CAR?

Select Your Answer (Keyboard: A, B, C, D)
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Correct Answer

✅ Option b — 22

All Options:

  • A21
  • B22
  • C25
  • D28

Detailed Solution & Explanation

Let's look at the standard alphabetical positions of the letters (A=1,B=2,…,Z=26\displaystyle A=1\displaystyle \text{A}=1, B=2\displaystyle \text{B}=2, \dots, Z=26\displaystyle \text{Z}=26):
For **MAT**, the sum of the standard position values of the letters is:
M=13M=13\displaystyle \text{M} = 13
A=1A=1\displaystyle \text{A} = 1
T=20T=20\displaystyle \text{T} = 20
Sum=13+1+20=34Sum=13+1+20=34\displaystyle \text{Sum} = 13 + 1 + 20 = 34

Using the same standard alphabetical position logic for **CAR**:
C=3C=3\displaystyle \text{C} = 3
A=1A=1\displaystyle \text{A} = 1
R=18R=18\displaystyle \text{R} = 18
Sum=3+1+18=22Sum=3+1+18=22\displaystyle \text{Sum} = 3 + 1 + 18 = 22

*Note:* The clue E=6\displaystyle E=6 (where standard E=5\displaystyle E=5) appears to be an isolated typographical error in the textbook question, as the standard positional sum works perfectly for both MAT ($34$) and CAR ($22$).

Hence, **Option B** is the correct answer.

About This Chapter: Number Series, Coding and Decoding

Paper

Paper 3: Quantitative Aptitude

Weightage

5 Marks

Key Topics

Number series, Coding & Decoding, Odd man out

This chapter covers Number series, Coding & Decoding, Odd man out and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 5 Marks weightage. Focus on understanding core concepts rather than memorizing.

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