Measures of Central Tendency and DispersionMCQMTP Nov 21Question 3060 of 473
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Find the two numbers if AM and GM is $10and\displaystyle and6$ respectively.

Select Your Answer (Keyboard: A, B, C, D)
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Correct Answer

✅ Option d — $18, 2$

All Options:

  • A$6, 6$
  • B$12, 8$
  • C$9, 4$
  • D$18, 2$

Detailed Solution & Explanation

**Step 1: Set up equations.** Let the two numbers be a\displaystyle a and b\displaystyle b. a+b2=10⇒a+b=20a+b2=10\displaystyle \frac{a+b}{2} = 10 \Rightarrow a + b = 20 ab=6⇒ab=36ab=6\displaystyle \sqrt{ab} = 6 \Rightarrow ab = 36 **Step 2: Solve.** (a−b)2=(a+b)2−4ab=400−144=256(a-b)^2 = (a+b)^2 - 4ab = 400 - 144 = 256 ∣a−b∣=16|a-b| = 16 From a+b=20\displaystyle a + b = 20 and a−b=16\displaystyle a - b = 16: a=18,b=2a = 18, \quad b = 2 **Verification:** - AM = (18+2)/2=10\displaystyle (18+2)/2 = 10 ✓ - GM = 18×2=36=6\displaystyle 18×2=36=6\displaystyle \sqrt{18 \times 2} = \sqrt{36} = 6 ✓ The numbers are $18and\displaystyle and2$ = **Option D**. Note: The exam key says C ($9, 4$) but: AM of $9,4$ = $6.5 ≠\displaystyle \neq 10\displaystyle . The correct answer is **D** ($18, 2). Hence, **Option D** is the correct answer.

About This Chapter: Measures of Central Tendency and Dispersion

Paper

Paper 3: Quantitative Aptitude

Weightage

12-15 Marks

Key Topics

Mean, Median, Mode, Range, Mean Deviation, Standard Deviation

The core foundation of Statistics. This chapter covers Mean (Arithmetic, Geometric, Harmonic), Median, Mode, and their properties. It also explores measures of spread like Range, Mean Deviation, Standard Deviation, and Quartile Deviation.

View Official ICAI Syllabus

Exam Strategy Tip

Do not just memorize formulas; ICAI loves asking about the mathematical properties (e.g., 'sum of deviations from the AM is always zero'). You can usually eliminate 2 options just by knowing the properties.

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