Sequence and SeriesMCQMTP May 18Question 1784 of 212
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For what value of x\displaystyle x; the sequence x+1,3x,4x+2\displaystyle x+1, 3x, 4x+2 are in AP?

Options

A3\displaystyle 3
B2\displaystyle 2
C4\displaystyle 4
D5\displaystyle 5
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Correct Answer

Option a3\displaystyle 3

All Options:

  • A3\displaystyle 3
  • B2\displaystyle 2
  • C4\displaystyle 4
  • D5\displaystyle 5

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Detailed Solution & Explanation

Since the terms x+1,3x,4x+2\displaystyle x+1, 3x, 4x+2 are in A.P., the common differences must be equal:
3x(x+1)=(4x+2)3x3x - (x+1) = (4x+2) - 3x
2x1=x+22x - 1 = x + 2
x=3x = 3

Let us verify: for x=3\displaystyle x = 3, the terms are 4,9,14\displaystyle 4, 9, 14, which form an A.P. with a common difference of 5\displaystyle 5.
Hence, **Option A** is the correct answer.

About This Chapter: Sequence and Series

Paper

Paper 3: Quantitative Aptitude

Weightage

4-6 Marks

Key Topics

Arithmetic & Geometric Progressions

This chapter covers Arithmetic Progressions (AP) and Geometric Progressions (GP). Students learn how to find the nth term, sum of n terms, arithmetic/geometric means, and sum to infinity of a GP.

View Official ICAI Syllabus

Exam Strategy Tip

For complex 'sum of series' questions, a great hack is to substitute n = 1 and n = 2 into the question and the options to see which one matches, completely bypassing the formula.

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