Sequence and SeriesMCQMTP March 21Question 1795 of 212
All Questions

Insert 4\displaystyle 4 A.M.'s between 3\displaystyle 3 and 18\displaystyle 18:

Options

A12,15,9,6\displaystyle 12,15,9,6
B6,9,12,15\displaystyle 6,9,12,15
C9,6,12,15\displaystyle 9,6,12,15
D15,12,9,6\displaystyle 15,12,9,6
For any discrepancies in this question, email contact@cadada.in

Correct Answer

Option b6,9,12,15\displaystyle 6,9,12,15

All Options:

  • A12,15,9,6\displaystyle 12,15,9,6
  • B6,9,12,15\displaystyle 6,9,12,15
  • C9,6,12,15\displaystyle 9,6,12,15
  • D15,12,9,6\displaystyle 15,12,9,6

Ad

Detailed Solution & Explanation

Let the four arithmetic means be A1,A2,A3,A4\displaystyle A_1, A_2, A_3, A_4.
Then, the sequence 3,A1,A2,A3,A4,18\displaystyle 3, A_1, A_2, A_3, A_4, 18 is in A.P.
Here:
First term a=3\displaystyle a = 3
Total number of terms N=6\displaystyle N = 6
Sixth term t6=18\displaystyle t_6 = 18.

Using the A.P. formula:
t6=a+5dt_6 = a + 5d
18=3+5d18 = 3 + 5d
15=5d    d=315 = 5d \implies d = 3

Now, calculate the four means:
A1=a+d=3+3=6A_1 = a + d = 3 + 3 = 6
A2=a+2d=3+6=9A_2 = a + 2d = 3 + 6 = 9
A3=a+3d=3+9=12A_3 = a + 3d = 3 + 9 = 12
A4=a+4d=3+12=15A_4 = a + 4d = 3 + 12 = 15
So the four AMs are 6,9,12,15\displaystyle 6, 9, 12, 15.
Hence, **Option B** is the correct answer.

About This Chapter: Sequence and Series

Paper

Paper 3: Quantitative Aptitude

Weightage

4-6 Marks

Key Topics

Arithmetic & Geometric Progressions

This chapter covers Arithmetic Progressions (AP) and Geometric Progressions (GP). Students learn how to find the nth term, sum of n terms, arithmetic/geometric means, and sum to infinity of a GP.

View Official ICAI Syllabus

Exam Strategy Tip

For complex 'sum of series' questions, a great hack is to substitute n = 1 and n = 2 into the question and the options to see which one matches, completely bypassing the formula.

Related Comparison Tables

More Questions from Sequence and Series

Ready to Master Sequence and Series?

Practice all 212 questions with instant feedback, earn XP, track your streaks, and ace your CA Foundation exam.

Start Practicing — It's Free