Sequence and SeriesMCQMTP June 24 Series IQuestion 1813 of 212
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The first, second and seventh term of an AP are in G.P. and the common difference is 2\displaystyle 2, the 2nd\displaystyle 2^{nd} term of A.P. is:

Options

A5/2\displaystyle 5/2
B2
C3/2\displaystyle 3/2
D1/2\displaystyle 1/2
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Correct Answer

Option a5/2\displaystyle 5/2

All Options:

  • A5/2\displaystyle 5/2
  • B2
  • C3/2\displaystyle 3/2
  • D1/2\displaystyle 1/2

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Detailed Solution & Explanation

Let the first term of the A.P. be a\displaystyle a and the common difference be d=2\displaystyle d = 2.
The terms are:
First term: t1=a\displaystyle t_1 = a
Second term: t2=a+d=a+2\displaystyle t_2 = a + d = a + 2
Seventh term: t7=a+6d=a+12\displaystyle t_7 = a + 6d = a + 12

Since t1,t2,t7\displaystyle t_1, t_2, t_7 are in G.P.:
(t2)2=t1t7(t_2)^2 = t_1 \cdot t_7
(a+2)2=a(a+12)(a+2)^2 = a(a+12)
a2+4a+4=a2+12aa^2 + 4a + 4 = a^2 + 12a
8a=4    a=128a = 4 \implies a = \frac{1}{2}

The second term of the A.P. is:
t2=a+2=12+2=52t_2 = a + 2 = \frac{1}{2} + 2 = \frac{5}{2}
Hence, **Option A** is the correct answer.

About This Chapter: Sequence and Series

Paper

Paper 3: Quantitative Aptitude

Weightage

4-6 Marks

Key Topics

Arithmetic & Geometric Progressions

This chapter covers Arithmetic Progressions (AP) and Geometric Progressions (GP). Students learn how to find the nth term, sum of n terms, arithmetic/geometric means, and sum to infinity of a GP.

View Official ICAI Syllabus

Exam Strategy Tip

For complex 'sum of series' questions, a great hack is to substitute n = 1 and n = 2 into the question and the options to see which one matches, completely bypassing the formula.

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