Sequence and SeriesMCQPYQ Dec. 21Question 1832 of 212
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The sum of series 7+14+21+\displaystyle 7 + 14 + 21 + \dots to 17th\displaystyle 17^{th} term is:

Options

A1071
B971
C1171
D1271
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Correct Answer

Option a1071

All Options:

  • A1071
  • B971
  • C1171
  • D1271

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Detailed Solution & Explanation

The series is 7+14+21+\displaystyle 7 + 14 + 21 + \dots
This is an A.P. with:
First term a=7\displaystyle a = 7
Common difference d=7\displaystyle d = 7
Number of terms n=17\displaystyle n = 17.

Using the sum formula:
S17=172[2(7)+(171)7]S_{17} = \frac{17}{2} [2(7) + (17-1)7]
S17=172[14+112]S_{17} = \frac{17}{2} [14 + 112]
S17=172[126]=1763=1071S_{17} = \frac{17}{2} [126] = 17 \cdot 63 = 1071
Hence, **Option A** is the correct answer.

About This Chapter: Sequence and Series

Paper

Paper 3: Quantitative Aptitude

Weightage

4-6 Marks

Key Topics

Arithmetic & Geometric Progressions

This chapter covers Arithmetic Progressions (AP) and Geometric Progressions (GP). Students learn how to find the nth term, sum of n terms, arithmetic/geometric means, and sum to infinity of a GP.

View Official ICAI Syllabus

Exam Strategy Tip

For complex 'sum of series' questions, a great hack is to substitute n = 1 and n = 2 into the question and the options to see which one matches, completely bypassing the formula.

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