Sets, Relations and FunctionsMCQPYQ Nov. 19Question 1889 of 217
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(Ac)c=?\displaystyle (A^c)^c = ? Note: This que is from matrix (deleted topic).

Options

AA\displaystyle A
BAc\displaystyle A^c
CAT\displaystyle A^T
DA2T\displaystyle A^{2T}
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Correct Answer

Option aA\displaystyle A

All Options:

  • AA\displaystyle A
  • BAc\displaystyle A^c
  • CAT\displaystyle A^T
  • DA2T\displaystyle A^{2T}

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Detailed Solution & Explanation

In set theory, let U\displaystyle U be the universal set and A\displaystyle A be any subset of U\displaystyle U.
The complement of set A\displaystyle A, denoted by Ac\displaystyle A^c, is the set of all elements in U\displaystyle U that do not belong to A\displaystyle A:
Ac={xUxA}A^c = \{x \in U \mid x \notin A\}
Taking the complement of Ac\displaystyle A^c again:
(Ac)c={xUxAc}(A^c)^c = \{x \in U \mid x \notin A^c\}
Since xAc\displaystyle x \notin A^c implies that xA\displaystyle x \in A, we have:
(Ac)c=A(A^c)^c = A
(Note: Even if interpreted as matrices where c\displaystyle c represents the transpose T\displaystyle T, the double transpose of a matrix A\displaystyle A returns the original matrix: (AT)T=A\displaystyle (A^T)^T = A.)
Hence, **Option A** is the correct answer.

About This Chapter: Sets, Relations and Functions

Paper

Paper 3: Quantitative Aptitude

Weightage

3-5 Marks

Key Topics

Sets, Relations, Functions

This chapter covers Sets, Relations, Functions and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

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Exam Strategy Tip

This topic carries 3-5 Marks weightage. Focus on understanding core concepts rather than memorizing.

Key Concepts to Understand

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