In a town of $20,000$ families it was found that $40\%$ families buy newspaper $A$, $20\%$ families buy newspaper $B$ and $10\%$ families buy newspaper $C$, $5\%$ families buy $A$ and $B$, $3\%$ buy $B$ and $C$ and $4\%$ buy $A$ and $C$, if $2\%$ families buy all the three newspaper, then the number of families which buy only $A$ is:
Options
A6600
B6300
C3600
D600
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