The number of items in the set $\displaystyle A$ is $\displaystyle 40$; in the set $\displaystyle B$ is $\displaystyle 32$; in the set $\displaystyle C$ is $\displaystyle 50$; in both $\displaystyle A$ and $\displaystyle B$ is $\displaystyle 4$, in both $\displaystyle A$ and $\displaystyle C$ is $\displaystyle 5$; in both $\displaystyle B$ and $\displaystyle C$ is $\displaystyle 7$ in all the sets $\displaystyle 2$. How many are in at least one of the set?

Let $\displaystyle A = \{a, b, c, d, e\}$ then the number of proper subsets is

The numbers of proper subset of the set $\displaystyle (3, 4, 5, 6, 7)$ is

If $\displaystyle A = (1, 2, 3, 4, 5, 6, 7)$ and $\displaystyle B = (2, 4, 6, 8)$. Cardinal number of $\displaystyle A - B$ is:

$\displaystyle (A^c)^c = ?$ Note: This que is from matrix (deleted topic).

Two finite sets respectively have $\displaystyle x$ and $\displaystyle y$ number of elements. The total number of subsets of the first is $\displaystyle 56$ more than the total number of subsets of the second. The value of $\displaystyle x$ and $\displaystyle y$ respectively.

The set of cubes of the natural number is: