Sets, Relations and FunctionsMCQMTP March 21Question 1924 of 217
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If A={4,5}\displaystyle A = \{4, 5\}, B={2,3}\displaystyle B = \{2, 3\}, C={5,6}\displaystyle C = \{5, 6\} then A×(BC)\displaystyle A \times (B \cap C)

Options

A(2,5),(3,5)\displaystyle {(2, 5), (3, 5)}
B(4,2),(4,6)\displaystyle {(4, 2), (4, 6)}
C(4,3),(4,2)\displaystyle {(4, 3), (4, 2)}
Dnone of these
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Correct Answer

Option dnone of these

All Options:

  • A(2,5),(3,5)\displaystyle {(2, 5), (3, 5)}
  • B(4,2),(4,6)\displaystyle {(4, 2), (4, 6)}
  • C(4,3),(4,2)\displaystyle {(4, 3), (4, 2)}
  • Dnone of these

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Detailed Solution & Explanation

Given sets:
A={4,5}\displaystyle A = \{4, 5\}
B={2,3}\displaystyle B = \{2, 3\}
C={5,6}\displaystyle C = \{5, 6\}
First, let us find the intersection of B\displaystyle B and C\displaystyle C:
Since B\displaystyle B and C\displaystyle C have no elements in common, their intersection is the empty set:
BC=B \cap C = \emptyset
Now we compute the Cartesian product A×(BC)\displaystyle A \times (B \cap C):
A×=A \times \emptyset = \emptyset
Since the empty set \displaystyle \emptyset is not listed in Options A, B, or C, the correct answer is "none of these".
Hence, **Option D** is the correct answer.

About This Chapter: Sets, Relations and Functions

Paper

Paper 3: Quantitative Aptitude

Weightage

3-5 Marks

Key Topics

Sets, Relations, Functions

This chapter covers Sets, Relations, Functions and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 3-5 Marks weightage. Focus on understanding core concepts rather than memorizing.

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