Sets, Relations and FunctionsMCQMTP Dec 22 Series IIQuestion 1953 of 217
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Let A={1,2,3}\displaystyle A = \{1,2,3\} then the relation R={(1,1),(2,3),(2,2),(3,3),(1,2)}\displaystyle R = \{(1,1), (2,3), (2,2), (3,3), (1,2)\} is called

Options

ASymmetric
BTransitive
CReflexive
DEquivalence
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Correct Answer

Option cReflexive

All Options:

  • ASymmetric
  • BTransitive
  • CReflexive
  • DEquivalence

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Detailed Solution & Explanation

We are given set A={1,2,3}\displaystyle A = \{1,2,3\} and relation R={(1,1),(2,3),(2,2),(3,3),(1,2)}\displaystyle R = \{(1,1), (2,3), (2,2), (3,3), (1,2)\}.
Let's analyze the properties of R\displaystyle R:
1. **Reflexive**: Since (1,1),(2,2),(3,3)R\displaystyle (1,1), (2,2), (3,3) \in R, the relation is reflexive. This corresponds to Option C.
2. **Symmetric**: For the relation to be symmetric, since (1,2)R\displaystyle (1, 2) \in R, we must have (2,1)R\displaystyle (2, 1) \in R. But (2,1)R\displaystyle (2, 1) \notin R. Thus, the relation is not symmetric.
3. **Transitive**: For the relation to be transitive, since (1,2)R\displaystyle (1, 2) \in R and (2,3)R\displaystyle (2, 3) \in R, we must have (1,3)R\displaystyle (1, 3) \in R. But (1,3)R\displaystyle (1, 3) \notin R. Thus, the relation is not transitive.
Since the relation is not symmetric and not transitive, it cannot be an equivalence relation.
Therefore, the relation is only reflexive.
*Note: The relation is reflexive, which corresponds to Option C. The textbook answer key incorrectly lists Option D (Equivalence) as the correct choice.*
Hence, **Option C** is the correct answer.

About This Chapter: Sets, Relations and Functions

Paper

Paper 3: Quantitative Aptitude

Weightage

3-5 Marks

Key Topics

Sets, Relations, Functions

This chapter covers Sets, Relations, Functions and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

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Exam Strategy Tip

This topic carries 3-5 Marks weightage. Focus on understanding core concepts rather than memorizing.

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