Set, Relations and FunctionsPYQ Nov. 18Question 1958 of 217
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If A={1,2,3,4}\displaystyle A = \{1, 2, 3, 4\} and B={1,4,9,16,25}\displaystyle B = \{1, 4, 9, 16, 25\} is a function f\displaystyle f is defined from set A\displaystyle A to B\displaystyle B where f(x)=x2\displaystyle f(x) = x^2 then the range of f\displaystyle f is:

Options

A{1,2,3,4}\displaystyle \{1, 2, 3, 4\}
B{1,4,9,16}\displaystyle \{1, 4, 9, 16\}
C{1,4,9,16,25}\displaystyle \{1, 4, 9, 16, 25\}
DNone of these
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Correct Answer

✅ Option b — {1,4,9,16}\displaystyle \{1, 4, 9, 16\}

All Options:

  • A{1,2,3,4}\displaystyle \{1, 2, 3, 4\}
  • B{1,4,9,16}\displaystyle \{1, 4, 9, 16\}
  • C{1,4,9,16,25}\displaystyle \{1, 4, 9, 16, 25\}
  • DNone of these

Detailed Solution & Explanation

We are given domain A={1,2,3,4}\displaystyle A = \{1, 2, 3, 4\}, codomain B={1,4,9,16,25}\displaystyle B = \{1, 4, 9, 16, 25\}, and function f:A→B\displaystyle f: A \to B defined by f(x)=x2\displaystyle f(x) = x^2.
The range of the function is the set of images of the elements of the domain A\displaystyle A under f\displaystyle f:
- f(1)=12=1\displaystyle f(1) = 1^2 = 1
- f(2)=22=4\displaystyle f(2) = 2^2 = 4
- f(3)=32=9\displaystyle f(3) = 3^2 = 9
- f(4)=42=16\displaystyle f(4) = 4^2 = 16
Therefore, the range of the function is:
Range(f)={1,4,9,16}\text{Range}(f) = \{1, 4, 9, 16\}
*Note: The range is {1,4,9,16}\displaystyle \{1, 4, 9, 16\}, which corresponds to Option B. The textbook answer key incorrectly lists Option A (which is the domain A\displaystyle A) as the correct choice.*
Hence, **Option B** is the correct answer.

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