Set, Relations and FunctionsMTP Nov 21Question 1980 of 217
All Questions

If f(x)=x2−1\displaystyle f(x) = x^2-1 and g(x)=2x+3\displaystyle g(x) = 2x+3 then gof(3)\displaystyle gof(3)

Options

A71
B61
C41
D19
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Correct Answer

✅ Option b — 61

All Options:

  • A71
  • B61
  • C41
  • D19

Detailed Solution & Explanation

Let us analyze the literal printed question and the likely intended full question:

**1. Literal Evaluation of g(f(3))\displaystyle g(f(3)):**
Given the functions:
f(x)=x2−1f(x) = x^2 - 1
g(x)=2x+3g(x) = 2x + 3
We evaluate f(3)\displaystyle f(3):
f(3)=32−1=9−1=8f(3) = 3^2 - 1 = 9 - 1 = 8
Now we substitute this into g(x)\displaystyle g(x) to find g(f(3))\displaystyle g(f(3)):
g(f(3))=g(8)=2(8)+3=16+3=19g(f(3)) = g(8) = 2(8) + 3 = 16 + 3 = 19
This corresponds to **Option D**.

**2. Source of Discrepancy & Truncation Error:**
This question (from MTP Nov 21) is a truncated version of a well-known past exam question (e.g., PYQ Dec 21, which is Question 2 in this set). The full question was:
Find [f∘g](3)−[g∘f](−3)\text{Find } [f \circ g](3) - [g \circ f](-3)
Let's solve the full question:
- g(3)=2(3)+3=9  ⟹  f(g(3))=92−1=80\displaystyle g(3) = 2(3) + 3 = 9 \implies f(g(3)) = 9^2 - 1 = 80
- f(−3)=(−3)2−1=8  ⟹  g(f(−3))=2(8)+3=19\displaystyle f(-3) = (-3)^2 - 1 = 8 \implies g(f(-3)) = 2(8) + 3 = 19
- Difference: 80−19=61\displaystyle 80 - 19 = 61.
This matches **Option B** (61).

Because the question was truncated during printing, the literal answer is 19\displaystyle 19 (Option D), but the official exam key retains the original value **Option B** (61) based on the untruncated problem.

Hence, **Option B** is the correct answer (according to the textbook key), but the mathematically proven correct value for the printed text is 19\displaystyle 19 (**Option D**).

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