Sets, Relations and FunctionsMCQMTP March 22Question 1990 of 217
All Questions

If f(x)=2+x2x\displaystyle f(x)=\frac{2+x}{2-x}, then f1(x)\displaystyle f^{-1}(x)

Options

A2(x1)x+1\displaystyle \frac{2(x-1)}{x+1}
B2(x+1)x1\displaystyle \frac{2(x+1)}{x-1}
C(x+1)x1\displaystyle \frac{(x+1)}{x-1}
D(x1)x+1\displaystyle \frac{(x-1)}{x+1}
For any discrepancies in this question, email contact@cadada.in

Correct Answer

Option a2(x1)x+1\displaystyle \frac{2(x-1)}{x+1}

All Options:

  • A2(x1)x+1\displaystyle \frac{2(x-1)}{x+1}
  • B2(x+1)x1\displaystyle \frac{2(x+1)}{x-1}
  • C(x+1)x1\displaystyle \frac{(x+1)}{x-1}
  • D(x1)x+1\displaystyle \frac{(x-1)}{x+1}

Ad

Detailed Solution & Explanation

To find the inverse function f1(x)\displaystyle f^{-1}(x), we set y=f(x)\displaystyle y = f(x) and solve for x\displaystyle x in terms of y\displaystyle y:
y=2+x2xy = \frac{2 + x}{2 - x}
Multiply both sides by (2x)\displaystyle (2 - x):
y(2x)=2+xy(2 - x) = 2 + x
2yxy=2+x2y - xy = 2 + x
Rearrange the terms to group all x\displaystyle x terms on one side:
2y2=x+xy2y - 2 = x + xy
Factor out x\displaystyle x from the right side and factor out 2\displaystyle 2 from the left side:
2(y1)=x(1+y)2(y - 1) = x(1 + y)<br>Divideby\displaystyle <br>Divide by(1 + y):<br><spanclass="katexdisplay"><spanclass="katex"><spanclass="katexmathml"><mathxmlns="http://www.w3.org/1998/Math/MathML"display="block"><semantics><mrow><mi>x</mi><mo>=</mo><mfrac><mrow><mn>2</mn><mostretchy="false">(</mo><mi>y</mi><mo></mo><mn>1</mn><mostretchy="false">)</mo></mrow><mrow><mi>y</mi><mo>+</mo><mn>1</mn></mrow></mfrac></mrow><annotationencoding="application/xtex">x=2(y1)y+1</annotation></semantics></math></span><spanclass="katexhtml"ariahidden="true"><spanclass="base"><spanclass="strut"style="height:0.4306em;"></span><spanclass="mordmathnormal">x</span><spanclass="mspace"style="marginright:0.2778em;"></span><spanclass="mrel">=</span><spanclass="mspace"style="marginright:0.2778em;"></span></span><spanclass="base"><spanclass="strut"style="height:2.3074em;verticalalign:0.8804em;"></span><spanclass="mord"><spanclass="mopennulldelimiter"></span><spanclass="mfrac"><spanclass="vlisttvlistt2"><spanclass="vlistr"><spanclass="vlist"style="height:1.427em;"><spanstyle="top:2.314em;"><spanclass="pstrut"style="height:3em;"></span><spanclass="mord"><spanclass="mordmathnormal"style="marginright:0.03588em;">y</span><spanclass="mspace"style="marginright:0.2222em;"></span><spanclass="mbin">+</span><spanclass="mspace"style="marginright:0.2222em;"></span><spanclass="mord">1</span></span></span><spanstyle="top:3.23em;"><spanclass="pstrut"style="height:3em;"></span><spanclass="fracline"style="borderbottomwidth:0.04em;"></span></span><spanstyle="top:3.677em;"><spanclass="pstrut"style="height:3em;"></span><spanclass="mord"><spanclass="mord">2</span><spanclass="mopen">(</span><spanclass="mordmathnormal"style="marginright:0.03588em;">y</span><spanclass="mspace"style="marginright:0.2222em;"></span><spanclass="mbin"></span><spanclass="mspace"style="marginright:0.2222em;"></span><spanclass="mord">1</span><spanclass="mclose">)</span></span></span></span><spanclass="vlists"></span></span><spanclass="vlistr"><spanclass="vlist"style="height:0.8804em;"><span></span></span></span></span></span><spanclass="mclosenulldelimiter"></span></span></span></span></span></span><br>Replacing\displaystyle :<br><span class="katex-display"><span class="katex"><span class="katex-mathml"><math xmlns="http://www.w3.org/1998/Math/MathML" display="block"><semantics><mrow><mi>x</mi><mo>=</mo><mfrac><mrow><mn>2</mn><mo stretchy="false">(</mo><mi>y</mi><mo>−</mo><mn>1</mn><mo stretchy="false">)</mo></mrow><mrow><mi>y</mi><mo>+</mo><mn>1</mn></mrow></mfrac></mrow><annotation encoding="application/x-tex">x = \frac{2(y - 1)}{y + 1}</annotation></semantics></math></span><span class="katex-html" aria-hidden="true"><span class="base"><span class="strut" style="height:0.4306em;"></span><span class="mord mathnormal">x</span><span class="mspace" style="margin-right:0.2778em;"></span><span class="mrel">=</span><span class="mspace" style="margin-right:0.2778em;"></span></span><span class="base"><span class="strut" style="height:2.3074em;vertical-align:-0.8804em;"></span><span class="mord"><span class="mopen nulldelimiter"></span><span class="mfrac"><span class="vlist-t vlist-t2"><span class="vlist-r"><span class="vlist" style="height:1.427em;"><span style="top:-2.314em;"><span class="pstrut" style="height:3em;"></span><span class="mord"><span class="mord mathnormal" style="margin-right:0.03588em;">y</span><span class="mspace" style="margin-right:0.2222em;"></span><span class="mbin">+</span><span class="mspace" style="margin-right:0.2222em;"></span><span class="mord">1</span></span></span><span style="top:-3.23em;"><span class="pstrut" style="height:3em;"></span><span class="frac-line" style="border-bottom-width:0.04em;"></span></span><span style="top:-3.677em;"><span class="pstrut" style="height:3em;"></span><span class="mord"><span class="mord">2</span><span class="mopen">(</span><span class="mord mathnormal" style="margin-right:0.03588em;">y</span><span class="mspace" style="margin-right:0.2222em;"></span><span class="mbin">−</span><span class="mspace" style="margin-right:0.2222em;"></span><span class="mord">1</span><span class="mclose">)</span></span></span></span><span class="vlist-s">​</span></span><span class="vlist-r"><span class="vlist" style="height:0.8804em;"><span></span></span></span></span></span><span class="mclose nulldelimiter"></span></span></span></span></span></span><br>Replacingywith\displaystyle withx$ to express the inverse function, we get:
f1(x)=2(x1)x+1f^{-1}(x) = \frac{2(x - 1)}{x + 1}

Hence, **Option A** is the correct answer.

About This Chapter: Sets, Relations and Functions

Paper

Paper 3: Quantitative Aptitude

Weightage

3-5 Marks

Key Topics

Sets, Relations, Functions

This chapter covers Sets, Relations, Functions and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 3-5 Marks weightage. Focus on understanding core concepts rather than memorizing.

Related Comparison Tables

More Questions from Sets, Relations and Functions

Ready to Master Sets, Relations and Functions?

Practice all 217 questions with instant feedback, earn XP, track your streaks, and ace your CA Foundation exam.

Start Practicing — It's Free