The price of scooter and moped are in the ratio 7:9 . The price of moped is Rs. 1600 more than that of scooter. Then the price of moped is:

Option a: Rs. 7200. Solution: Let PS be the price of the scooter and PM be the price of the moped. The problem states that the prices of the scooter and moped are in the ratio 7:9 . This can be expressed mathematically as: PS/PM = 7/9 From this ratio, we can express PS in terms of PM : PS = 7/9 PM (Equation 1) The problem also states that the price of the moped is $

The price of scooter and moped are in the ratio $7:9$. The price of moped is $\text{Rs.} 1600$ more than that of scooter. Then the price of moped is:

The correct answer is Option a: $\text{Rs.} 7200$. Let $P_S$ be the price of the scooter and $P_M$ be the price of the moped. The problem states that the prices of the scooter and moped are in the ratio $7:9$. This can be expressed mathematically as: $$ \frac{P_S}{P_M} = \frac{7}{9} $$ From this ratio, we can express $P_S$ in terms of $P_M$: $$ P_S = \frac{7}{9} P_M \quad \text{(Equation 1)} $$ The problem also states that the price of the moped is $\text

Ratio, Proportion, Indices, LogarithmMCQMTP Dec 22 Series IIQuestion 842 of 305

All Questions

The price of scooter and moped are in the ratio $\displaystyle 7:9$ . The price of moped is $\displaystyle \text{Rs.} 1600$ more than that of scooter. Then the price of moped is:

Options

\displaystyle \text{Rs.} 7200

\displaystyle \text{Rs.} 5600

\displaystyle \text{Rs.} 800

\displaystyle \text{Rs.} 700

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Correct Answer

✅ Option a — $\displaystyle \text{Rs.} 7200$

All Options:

A $\displaystyle \text{Rs.} 7200$
B $\displaystyle \text{Rs.} 5600$
C $\displaystyle \text{Rs.} 800$
D $\displaystyle \text{Rs.} 700$

Detailed Solution & Explanation

Let

\displaystyle P_S

be the price of the scooter and

\displaystyle P_M

be the price of the moped. The problem states that the prices of the scooter and moped are in the ratio

\displaystyle 7:9

. This can be expressed mathematically as:

\frac{P_S}{P_M} = \frac{7}{9}

From this ratio, we can express

\displaystyle P_S

in terms of

\displaystyle P_M

P_S = \frac{7}{9} P_M \quad \text{(Equation 1)}

The problem also states that the price of the moped is $\text

About This Chapter: Ratio, Proportion, Indices, Logarithm

Paper

Paper 3: Quantitative Aptitude

Weightage

5-7 Marks

Key Topics

Ratio, Proportion, Indices, Logarithms

This chapter covers Ratio, Proportion, Indices, Logarithms and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 5-7 Marks weightage. Focus on understanding core concepts rather than memorizing.

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The price of scooter and moped are in the ratio 7:9\displaystyle 7:97:9. The price of moped is Rs.1600\displaystyle \text{Rs.} 1600Rs.1600 more than that of scooter. Then the price of moped is: