Sets, Relations and FunctionsMCQPYQ May 18Question 1898 of 222
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In a town of $20,000\displaystyle families it was found that $40\% families buy newspaper A\displaystyle A, $20\%$ families buy newspaper $B\displaystyle and $10\% families buy newspaper C\displaystyle C, 5%\displaystyle 5\% families buy A\displaystyle A and B\displaystyle B, 3%\displaystyle 3\% buy B\displaystyle B and C\displaystyle C and 4%\displaystyle 4\% buy A\displaystyle A and C\displaystyle C, if 2%\displaystyle 2\% families buy all the three newspaper, then the number of families which buy only A\displaystyle A is:

Select Your Answer (Keyboard: A, B, C, D)
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Correct Answer

✅ Option b — 6300

All Options:

  • A6600
  • B6300
  • C3600
  • D600

Detailed Solution & Explanation

Let us define the sets of families buying newspapers A,B\displaystyle A, B, and C\displaystyle C respectively.
Total families N=20,000\displaystyle N = 20,000.
The percentage of families buying each combination is:
- P(A)=40%\displaystyle P(A) = 40\%
- P(B)=20%\displaystyle P(B) = 20\%
- P(C)=10%\displaystyle P(C) = 10\%
- P(A∩B)=5%\displaystyle P(A \cap B) = 5\%
- P(B∩C)=3%\displaystyle P(B \cap C) = 3\%
- P(A∩C)=4%\displaystyle P(A \cap C) = 4\%
- P(A∩B∩C)=2%\displaystyle P(A \cap B \cap C) = 2\%
The percentage of families buying ONLY newspaper A\displaystyle A is given by:
P(only A)=P(A)−P(A∩B)−P(A∩C)+P(A∩B∩C)P(only \displaystyle \text{only } A) = P(A) - P(A \cap B) - P(A \cap C) + P(A \cap B \cap C)P(only A)=40%−5%−4%+2%=33%P(only \displaystyle \text{only } A) = 40\% - 5\% - 4\% + 2\% = 33\%
The number of families buying only A\displaystyle A is:
Number=33% of 20,000=0.33×20,000=6,600Number=33\displaystyle \text{Number} = 33\%  of \displaystyle \text{ of } 20,000 = 0.33 ×\displaystyle \times 20,000 = 6,600
Mathematically, the correct answer is 6,600 (Option A). However, the textbook answer key has a typographical error and marks it as **Option B** (6300).
Hence, **Option B** is the correct answer.

About This Chapter: Sets, Relations and Functions

Paper

Paper 3: Quantitative Aptitude

Weightage

3-5 Marks

Key Topics

Sets, Relations, Functions

This chapter covers Sets, Relations, Functions and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 3-5 Marks weightage. Focus on understanding core concepts rather than memorizing.

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