Ratio, Proportion, Indices, LogarithmsPYQ Jan 26Question 4249 of 220
All Questions

In India, an examination is conducted in two sessions. In the first session the ratio of boys to girls among 455 students is 8: 5. If 50 new girls are admitted in the second session, how many new boys must be admitted so that the ratio of girls to boys becomes 3: 4?

Options

A20
B30
C40
D50
For any discrepancies in this question, email contact@cadada.in

Correct Answer

Option a20

All Options:

  • A20
  • B30
  • C40
  • D50

Detailed Solution & Explanation

Given:
- Total number of students in the first session = 455\displaystyle 455
- Ratio of boys to girls in the first session = 8:5\displaystyle 8 : 5

Let us calculate the number of boys and girls in the first session:
Sum of ratio terms=8+5=13\text{Sum of ratio terms} = 8 + 5 = 13
Number of boys=813×455=8×35=280\text{Number of boys} = \frac{8}{13} \times 455 = 8 \times 35 = 280
Number of girls=513×455=5×35=175\text{Number of girls} = \frac{5}{13} \times 455 = 5 \times 35 = 175

In the second session:
- 50\displaystyle 50 new girls are admitted. So, new number of girls = 175+50=225\displaystyle 175 + 50 = 225.
- Let x\displaystyle x be the number of new boys admitted. So, new number of boys = 280+x\displaystyle 280 + x.
- The new ratio of **girls to boys** is given as 3:4\displaystyle 3 : 4.

Set up the proportion:
New number of girlsNew number of boys=34\frac{\text{New number of girls}}{\text{New number of boys}} = \frac{3}{4}225280+x=34\frac{225}{280 + x} = \frac{3}{4}
Cross-multiply to solve for x\displaystyle x:
3(280+x)=4(225)3(280 + x) = 4(225)
840+3x=900840 + 3x = 900
3x=9008403x = 900 - 840
3x=603x = 60
x=20x = 20
Thus, 20\displaystyle 20 new boys must be admitted.

Hence, **Option A** is the correct answer.

More Questions from Ratio, Proportion, Indices, Logarithms

Ready to Master Ratio, Proportion, Indices, Logarithms?

Practice all 220 questions with instant feedback, earn XP, track your streaks, and ace your CA Foundation exam.

Start Practicing — It's Free