The ratio of the prices of two houses was $16:23\displaystyle . Two years later when the price of the first has increased by $10\% and that of the second by $\displaystyle$$\displaystyle \text{Rs.}$ 477, the ratio of the prices becomes $11:20$. Find the original prices of the two houses.

$3x-2:5x+6$ the duplicate ratio of $2:3$ then find the value $\displaystyle x$.

If the ratio of two numbers is $7:11$\displaystyle . If$7$ is added to each number then the new ratio will be $2:3$ then the numbers are.

If $\displaystyle x:y=z:7=4:11$ then $\displaystyle$$\displaystyle \frac{x+y+z}{z}$ is

The ratio of two numbers are $3:4$. The difference of their squares is $28$ greater is:

The price of scooter and moped are in the ratio $7:9$. The price of moped is $₹1,600$ more than that of scooter. Then the price of moped is:

If $\displaystyle A:B=3:7$, then $3a+2b:4a+5b=?$