Ratio, Proportion, Indices, LogarithmMCQMTP March 22Question 909 of 302
All Questions

If P=x1/3+x−1/3\displaystyle P = x^{1/3} + x^{-1/3} then find value of $3P^3 - 9P$

Select Your Answer (Keyboard: A, B, C, D)
For any discrepancies in this question, email contact@cadada.in

Correct Answer

✅ Option c — $3(x+1/x)$

All Options:

  • A3\displaystyle 3
  • B1/2(x+1/x)\displaystyle 1/2(x+1/x)
  • C$3(x+1/x)$
  • D$2(x+1/x)$

Detailed Solution & Explanation

We are given:
P=x1/3+x−1/3P = x^{1/3} + x^{-1/3}

Let us cube both sides of the equation using the algebraic identity:
(u+v)3=u3+v3+3uv(u+v)(u+v)^3 = u^3 + v^3 + 3uv(u+v)

Here, let u=x1/3\displaystyle u = x^{1/3} and v=x−1/3\displaystyle v = x^{-1/3}. The product uv\displaystyle uv is:
uv=x1/3×x−1/3=x1/3−1/3=x0=1uv = x^{1/3} ×\displaystyle \times x^{-1/3} = x^{1/3 - 1/3} = x^0 = 1

Now, applying the identity:
P3=(x1/3)3+(x−1/3)3+3(1)(x1/3+x−1/3)P^3 = \left( x^{1/3} \right)^3 + \left( x^{-1/3} \right)^3 + 3(1)\left( x^{1/3} + x^{-1/3} \right)
P3=x+x−1+3PP^3 = x + x^{-1} + 3P
P3=x+1x+3PP^3 = x + 1x+3P\displaystyle \frac{1}{x} + 3P

Rearranging the terms by moving $3P\displaystyle to the left side:<br><span class="katex-display"><span class="katex"><span class="katex-mathml"><math xmlns="http://www.w3.org/1998/Math/MathML" display="block"><semantics><mrow><msup><mi>P</mi><mn>3</mn></msup><mo>−</mo><mn>3</mn><mi>P</mi><mo>=</mo><mi>x</mi><mo>+</mo><mfrac><mn>1</mn><mi>x</mi></mfrac></mrow><annotation encoding="application/x-tex">P^3 - 3P = x + 1x\displaystyle \frac{1}{x}</annotation></semantics></math></span><span class="katex-html" aria-hidden="true"><span class="base"><span class="strut" style="height:0.9474em;vertical-align:-0.0833em;"></span><span class="mord"><span class="mord mathnormal" style="margin-right:0.13889em;">P</span><span class="msupsub"><span class="vlist-t"><span class="vlist-r"><span class="vlist" style="height:0.8641em;"><span style="top:-3.113em;margin-right:0.05em;"><span class="pstrut" style="height:2.7em;"></span><span class="sizing reset-size6 size3 mtight"><span class="mord mtight">3</span></span></span></span></span></span></span></span><span class="mspace" style="margin-right:0.2222em;"></span><span class="mbin">−</span><span class="mspace" style="margin-right:0.2222em;"></span></span><span class="base"><span class="strut" style="height:0.6833em;"></span><span class="mord">3</span><span class="mord mathnormal" style="margin-right:0.13889em;">P</span><span class="mspace" style="margin-right:0.2778em;"></span><span class="mrel">=</span><span class="mspace" style="margin-right:0.2778em;"></span></span><span class="base"><span class="strut" style="height:0.6667em;vertical-align:-0.0833em;"></span><span class="mord mathnormal">x</span><span class="mspace" style="margin-right:0.2222em;"></span><span class="mbin">+</span><span class="mspace" style="margin-right:0.2222em;"></span></span><span class="base"><span class="strut" style="height:2.0074em;vertical-align:-0.686em;"></span><span class="mord"><span class="mopen nulldelimiter"></span><span class="mfrac"><span class="vlist-t vlist-t2"><span class="vlist-r"><span class="vlist" style="height:1.3214em;"><span style="top:-2.314em;"><span class="pstrut" style="height:3em;"></span><span class="mord"><span class="mord mathnormal">x</span></span></span><span style="top:-3.23em;"><span class="pstrut" style="height:3em;"></span><span class="frac-line" style="border-bottom-width:0.04em;"></span></span><span style="top:-3.677em;"><span class="pstrut" style="height:3em;"></span><span class="mord"><span class="mord">1</span></span></span></span><span class="vlist-s">​</span></span><span class="vlist-r"><span class="vlist" style="height:0.686em;"><span></span></span></span></span></span><span class="mclose nulldelimiter"></span></span></span></span></span></span><br><br>We need to find the value of &#36;3P^3 - 9P. Factor out 3\displaystyle 3 from the expression:
3P3−9P=3(P3−3P)3P^3 - 9P = 3\left( P^3 - 3P \right)

Substituting the value of P3−3P\displaystyle P^3 - 3P:
3P3−9P=3(x+1x)3P^3 - 9P = 3\left( x + 1x\displaystyle \frac{1}{x} \right)

Hence, **Option C** is the correct answer.

About This Chapter: Ratio, Proportion, Indices, Logarithm

Paper

Paper 3: Quantitative Aptitude

Weightage

5-7 Marks

Key Topics

Ratio, Proportion, Indices, Logarithms

This chapter covers Ratio, Proportion, Indices, Logarithms and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 5-7 Marks weightage. Focus on understanding core concepts rather than memorizing.

More Questions from Ratio, Proportion, Indices, Logarithm

Ready to Master Ratio, Proportion, Indices, Logarithm?

Practice all 302 questions with instant feedback, earn XP, track your streaks, and ace your CA Foundation exam.

Start Practicing — It's Free