Ratio, Proportion, Indices, LogarithmMCQPYQ June 24Question 808 of 305

A fraction becomes $\displaystyle 1$ when $\displaystyle 3$ is added to the numerator and $\displaystyle 1$ is added to the denominator, but when the numerator and denominator are decreased by $\displaystyle 2$ and $\displaystyle 1$ respectively, it becomes $\displaystyle 1/2$ . The denominator of the fraction is:

\displaystyle 10

\displaystyle 6

\displaystyle 7

\displaystyle 8

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Correct Answer

✅ Option c — $\displaystyle 7$

Let the fraction be

\displaystyle \frac{n}{d}

, where

\displaystyle n

is the numerator and

\displaystyle d

is the denominator.
According to the first condition:

\frac{n + 3}{d + 1} = 1 \implies n + 3 = d + 1 \implies d = n + 2

According to the second condition:

\frac{n - 2}{d - 1} = \frac{1}{2}

Substitute the expression

\displaystyle d = n + 2

from the first condition into the second:

\frac{n - 2}{(n + 2) - 1} = \frac{1}{2}

\frac{n - 2}{n + 1} = \frac{1}{2}

Cross-multiplying:

2(n - 2) = n + 1

2n - 4 = n + 1 \implies n = 5

Now we substitute

\displaystyle n = 5

to find the denominator

\displaystyle d

d = n + 2 = 5 + 2 = 7

Paper

Paper 3: Quantitative Aptitude

Weightage

5-7 Marks

Key Topics

Ratio, Proportion, Indices, Logarithms

This chapter covers Ratio, Proportion, Indices, Logarithms and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

Exam Strategy Tip

This topic carries 5-7 Marks weightage. Focus on understanding core concepts rather than memorizing.

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