Ratio, Proportion, Indices, LogarithmMCQMTP June 22Question 837 of 305
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A person has asset worth of Rs.1,48,200\displaystyle \text{Rs.} 1,48,200. He wish to divide it amongst his wife, son and daughter in the ratio 3:2:1\displaystyle 3:2:1 respectively. From this assets share of his son will be.

Options

ARs.24,700\displaystyle \text{Rs.} 24,700
BRs.49,400\displaystyle \text{Rs.} 49,400
CRs.74,100\displaystyle \text{Rs.} 74,100
DRs.37,050\displaystyle \text{Rs.} 37,050
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Correct Answer

✅ Option b — Rs.49,400\displaystyle \text{Rs.} 49,400

All Options:

  • ARs.24,700\displaystyle \text{Rs.} 24,700
  • BRs.49,400\displaystyle \text{Rs.} 49,400
  • CRs.74,100\displaystyle \text{Rs.} 74,100
  • DRs.37,050\displaystyle \text{Rs.} 37,050

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Detailed Solution & Explanation

Let the total asset worth be A\displaystyle A. Given, A=Rs.1,48,200\displaystyle A = \text{Rs.} 1,48,200.
The asset is to be divided amongst his wife, son, and daughter in the ratio 3:2:1\displaystyle 3:2:1 respectively.
Let the share of the wife be SW\displaystyle S_W, the share of the son be SS\displaystyle S_S, and the share of the daughter be SD\displaystyle S_D.
According to the given ratio, we can write: SW:SS:SD=3:2:1S_W : S_S : S_D = 3 : 2 : 1 To find the individual shares, we first calculate the sum of the ratio parts. Sum of the ratio parts =3+2+1=6\displaystyle = 3 + 2 + 1 = 6.
The total asset A\displaystyle A is divided into 6\displaystyle 6 equal parts, where the wife receives 3\displaystyle 3 parts, the son receives 2\displaystyle 2 parts, and the daughter receives 1\displaystyle 1 part.
The fraction of the total asset that the son receives is given by the son's ratio part divided by the sum of the ratio parts. Fraction of son's share =Son’s ratio partSum of ratio parts=26\displaystyle = \frac{\text{Son's ratio part}}{\text{Sum of ratio parts}} = \frac{2}{6}.
This fraction can be simplified: 26=13\frac{2}{6} = \frac{1}{3} Now, to find the son's share (SS\displaystyle S_S), we multiply this fraction by the total asset worth A\displaystyle A. SS=13×AS_S = \frac{1}{3} \times A Substitute the value of A\displaystyle A: SS=13×Rs.1,48,200S_S = \frac{1}{3} \times \text{Rs.} 1,48,200 Perform the multiplication: SS=Rs.1,48,2003S_S = \text{Rs.} \frac{1,48,200}{3} SS=Rs.49,400S_S = \text{Rs.} 49,400 Thus, the share of the son will be Rs.49,400\displaystyle \text{Rs.} 49,400.
Comparing this result with the given options: (A) Rs.24,700\displaystyle \text{Rs.} 24,700 (B) Rs.49,400\displaystyle \text{Rs.} 49,400 (C) Rs.74,100\displaystyle \text{Rs.} 74,100 (D) Rs.37,050\displaystyle \text{Rs.} 37,050
Our calculated value matches Option (B). The share of the son is Rs.49,400\displaystyle \text{Rs.} 49,400. Hence, **Option B** is the correct answer.

About This Chapter: Ratio, Proportion, Indices, Logarithm

Paper

Paper 3: Quantitative Aptitude

Weightage

5-7 Marks

Key Topics

Ratio, Proportion, Indices, Logarithms

This chapter covers Ratio, Proportion, Indices, Logarithms and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 5-7 Marks weightage. Focus on understanding core concepts rather than memorizing.

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