Ratio, Proportion, Indices, LogarithmMCQMTP Jun 23 - Series IIQuestion 857 of 305
All Questions

The mean proportional between 12x2\displaystyle 12x^2 and 27y2\displaystyle 27y^2

Options

A18xy\displaystyle 18xy
B81xy\displaystyle 81xy
C8xy\displaystyle 8xy
D9xy\displaystyle 9xy
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Correct Answer

Option a18xy\displaystyle 18xy

All Options:

  • A18xy\displaystyle 18xy
  • B81xy\displaystyle 81xy
  • C8xy\displaystyle 8xy
  • D9xy\displaystyle 9xy

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Detailed Solution & Explanation

By definition, the mean proportional between two quantities a\displaystyle a and b\displaystyle b is given by:
Mean Proportional=ab\text{Mean Proportional} = \sqrt{a \cdot b}
Here, the two quantities are a=12x2\displaystyle a = 12x^2 and b=27y2\displaystyle b = 27y^2.
Substituting these values into the formula:
Mean Proportional=12x227y2\text{Mean Proportional} = \sqrt{12x^2 \cdot 27y^2}
Multiply the numerical coefficients and the variables:
Mean Proportional=(12×27)x2y2\text{Mean Proportional} = \sqrt{(12 \times 27) \cdot x^2 y^2}
Mean Proportional=324x2y2\text{Mean Proportional} = \sqrt{324 x^2 y^2}
Since 182=324\displaystyle 18^2 = 324, the square root of 324x2y2\displaystyle 324x^2y^2 is:
Mean Proportional=18xy\text{Mean Proportional} = 18xy
This matches **Option A**.
Hence, **Option A** is the correct answer.

About This Chapter: Ratio, Proportion, Indices, Logarithm

Paper

Paper 3: Quantitative Aptitude

Weightage

5-7 Marks

Key Topics

Ratio, Proportion, Indices, Logarithms

This chapter covers Ratio, Proportion, Indices, Logarithms and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 5-7 Marks weightage. Focus on understanding core concepts rather than memorizing.

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