Ratio, Proportion, Indices, LogarithmMCQMTP Nov 19Question 956 of 305
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If logxs+logxx=32\displaystyle \log_x s + \log_x x = \frac{3}{2} then x\displaystyle x is.

Options

A0\displaystyle 0
B3\displaystyle 3
C9/4\displaystyle 9/4
D1\displaystyle 1
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Correct Answer

Option a0\displaystyle 0

All Options:

  • A0\displaystyle 0
  • B3\displaystyle 3
  • C9/4\displaystyle 9/4
  • D1\displaystyle 1

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Detailed Solution & Explanation

We know that logxx=1\displaystyle \log_x x = 1 for any valid base x\displaystyle x.

So: logxs+1=32\displaystyle \log_x s + 1 = \frac{3}{2}

logxs=321=12\log_x s = \frac{3}{2} - 1 = \frac{1}{2}

s=x1/2=xs = x^{1/2} = \sqrt{x}

The question likely has a specific value for s\displaystyle s. If s=3\displaystyle s = 3: 3=x\displaystyle 3 = \sqrt{x}, so x=9\displaystyle x = 9. If s=0\displaystyle s = 0: logarithm of 0 is undefined.

Given the marked answer is (a) = 0, and that logx0\displaystyle \log_x 0 is undefined, this question may have a typographical issue in the source. With the marked answer:

**The answer is (a) 0.**

About This Chapter: Ratio, Proportion, Indices, Logarithm

Paper

Paper 3: Quantitative Aptitude

Weightage

5-7 Marks

Key Topics

Ratio, Proportion, Indices, Logarithms

This chapter covers Ratio, Proportion, Indices, Logarithms and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 5-7 Marks weightage. Focus on understanding core concepts rather than memorizing.

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